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Umnica [9.8K]
3 years ago
14

1 Balance each equation. Paragraph Styles Voice Sensity 2) Indicate the type of reaction by classifying each reaction as single

replacement (SR), double replacement (DR), decomposition (), synthesis (S), or combustion (C). 3) Give one sentence explaining how you classified each. 1. Al2(SO4)3 + Ca3(PO4)2 -> AIPO4 + CaSO4 Type of reaction: Why: T 2. NaCIO3 → NaCl + O2
​
Chemistry
1 answer:
nika2105 [10]3 years ago
6 0

1. Double replacement (DR)

2. Decomposition (D)

<h3>Further explanation</h3>

1. Al2(SO4)3 + Ca3(PO4)2 -> 2AIPO4 + 3CaSO4

Double replacement (DR) : there is an ion exchange between two ion compounds in the reactant to form two new ion compounds in the product

General form :

AB + CD -> AD + CB

2.  2NaCIO3 → 2NaCl + 3O2

Decomposition (D) : Reactant breakdown into simpler ones(reverse of combination)

General form :

AB ---> A + B

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A reaction between substances Y and Z is
Anuta_ua [19.1K]

Answer : The value of activation energy for this reaction is 108.318 kJ/mol

Explanation :

The Arrhenius equation is written as:

K=A\times e^{\frac{-Ea}{RT}}

Taking logarithm on both the sides, we get:

\ln k=-\frac{Ea}{RT}+\ln A             ............(1)

where,

k = rate constant  = 2.95\times 10^{-3}L/mol.s

Ea = activation energy  = ?

T = temperature = 435 K

R = gas constant  = 8.314 J/K.mole

A = pre-exponential factor  = 3.00\times 10^{+10}L/mol.s

Now we have to calculate the value of rate constant by putting the given values in equation 1, we get:

\ln (2.95\times 10^{-3}L/mol.s)=-\frac{Ea}{8.314J/K.mol\times 435K}+\ln (3.00\times 10^{10}L/mol.s)

Ea=108318.365J/mol=108.318kJ/mol

Therefore, the value of activation energy for this reaction is 108.318 kJ/mol

3 0
2 years ago
Please show work, im really confused so please help!!
Rama09 [41]
No because the mass of the empty beaker , mass of beaker  is not balanced the amount of alcohol in the beaker.
4 0
2 years ago
Which of the following is a chemical property? freezing point color ability to react with oxygen hardness
Alenkasestr [34]
<span>Oxidation or reaction with oxygen is a chemical property</span>
4 0
3 years ago
Read 2 more answers
If 0.2 g of nitrobenzene are added to 10.9 g of naphthalene, calculate the molality of the solution. (given: molar mass of nitro
In-s [12.5K]

Molality is defined as 1 mole of a solute in 1 kg of solvent.  

Molality=

\frac{Number of moles of solute}{Mass of solvent in kg}

Number of moles of solute, n=  

\frac{Given mass of the substance}{Molar mass of the substance}

Given mass of the nitrobenzene=0.2 g

Molar mass of the substance= 123.06 g mol⁻¹

Number of moles of nitrobenzene,  

n= \frac{0.2 }{123.06}

Number of moles of nitrobenzene, n= 0.0016  mol

Mass of 10.9 g of naphthalene in kg=0.0109  

Molality= \frac{0.0016}{0.0109 }

Molality= 0.146 m

7 0
3 years ago
Can someone do this for me i wasent there when we learned it
Anna11 [10]
I’ll do the first two for you.
4 0
3 years ago
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