Answer:
The right solution according to the question is provided below.
Explanation:
According to the question,
(a)
The initial conditions will be:
DO = 
= 
= 
The initial oxygen defict will be:
Do = 
= 
The initial BOD will be:
Lo = 
= 
= 
(b)
The time reach minimum DO:
tc = ![\frac{1}{(kr-kd)} ln{(\frac{0.76}{0.61} )[1-\frac{1.674(0.76-0.61)}{0.61\times 6.453} ]}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B%28kr-kd%29%7D%20ln%7B%28%5Cfrac%7B0.76%7D%7B0.61%7D%20%29%5B1-%5Cfrac%7B1.674%280.76-0.61%29%7D%7B0.61%5Ctimes%206.453%7D%20%5D%7D)
= 
By putting the values of log, we get
= 
The distance to reach minimum DO will be:
Xc = 
= 
= 
Answer:
Hello
12 grams
The mass of one mole of carbon-12 atoms is 12 grams.
Hope it helps You.....
Explanation:
I would say that if they would use the regular ones, they would not be able to see very far. as well with that i would add that they need special lenses to see far.
hope that this helps you! =)
For this, we use equations from the colligative properties of solutions specifically boiling point elevation and freezing point depression. The equations for these are expressed as:
ΔTb = kb m
where k is a boiling point elevation constant and m is the concentration in terms of molality
ΔTf = kf m
where k is a freezing point elevation <span>constant and m is the concentration in terms of molality
</span>
We use both expression to solve for the freezing point. For this case, concentration is the same. The equation will then be:
ΔTf = kf ( ΔTb / kb )
0-Tf = 1.86 (103.7 - 100 / 0.512 )
Tf = -13.4°C
