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3 years ago

5

If she suddenly dropped the books, this would increase their energy. If she instead decided to hold the books over her head, thi

s would increase their energy.

1 answer:

Anna35 [415]3 years ago

7 0

Answer:

the answer is is is true

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Stacy runs a paper chromatography experiment using the same ink, but two different solvents.

Pie

Answer:

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Explanation:

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3 years ago

Read 2 more answers

Metals experience plastic deformation when _____.

xxTIMURxx [149]

Metals experience plastic deformation when a specific amount of pressure and temperature is applied to them. Most metals have low specific heat. Because of their low specific heat, they easily get hot when heat is applied to them.

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3 years ago

When water vapor condenses, how much heat energy will be released into the atmosphere?

Leona [35]

<span><span>When water vapor condenses, 2260 joules/gram heat energy will be released into the atmosphere.

To add, </span>heat energy<span> <span>(or </span>thermal energy<span> or simply </span>heat) is defined as a form of energy<span> which transfers among particles in a substance (or system) by means of kinetic </span>energy<span> of those particles. In other words, under kinetic theory, the </span>heat<span> is transferred by particles bouncing into each other.</span></span></span>

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3 years ago

Two gas-containers, A and B, are connected with a valve. The first container, A, has a volume of 135 mL, and the second containe

stiv31 [10]

Answer:

85.5 mmHg is the pressure of the gas sample when the valve is opened.

Explanation:

The combined gas equation is,

$\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}$

where,

$P_1$ = initial pressure of gas in container A = 165 mmHg

$P_2$ = final pressure of gas = ?

$V_1$ = initial volume of gas in container A= $135 mL$

$V_2$ = final volume of gas = 135 mL + 117 mL = 252 mL

$T_1$ = initial temperature of gas in container A = $22.5^oC=273+22.5=295.5 K$

$T_2$ = final temperature of gas = $12.7^oC=273+12.7=285.7K$

Now put all the given values in the above equation, we get:

$P_2=\frac{P_1V_1\times T_2}{T_1\times V_2}$

$=\frac{165 mmHg\times 135 mL\times 285.7 K}{295.5 K\times 252 mL}$

$P_2=85.5 mmHg$

85.5 mmHg is the pressure of the gas sample when the valve is opened.

8 0

4 years ago

5. Given 18.5 grams of CHA and 24.0 grams of Oz the following reaction occurs. Calculate the number of grams of

ehidna [41]

Answer:

16.5 g of CO₂ are produced by 18.5 of methane and 24 g of O₂

Explanation:

This is a reaction of combustion:

CH₄ + 2O₂ → CO₂ + 2H₂O

1 mol of methane react to 2 moles of oxygen in order to produce 1 mol of carbon dioxide and 2 moles of water.

First of all, we determine the moles of each reactant:

18.5 g . 1mol/ 16g = 1.15 moles of methane

24 g . 1mol / 32g = 0.75 moles of oxygen

Now, we determine the limiting reactant:

1 mol of methane reacts to 2 moles of oyxgen

1.15 moles of methane may react to (1.15 . 2) /1 = 2.3 moles.

We only have 0.75 moles of O₂ and we need 2.3, that's why the oxygen is the limiting reagent, because we do not have enough oxygen for the reaction.

2 moles of O₂ produce 1 mol of CO₂

Then 0.75 moles may produce (0.75 . 1) /2 = 0.375 moles of CO₂

We convert the moles to mass → 0.375 mol . 44g /mol = 16.5 g

7 0

3 years ago