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3 years ago

What is the main difference between dispersal and vicariance?

Physics

1 answer:

ohaa [14]3 years ago

6 0

<span>One leads to allopatric speciation, whereas the other lead to sympatric speciation.</span>

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Can u answer 4 and 5 for me

Luda [366]

I don’t know what the answers are

8 0

4 years ago

A satellite in the shape of a solid sphere of mass 1,900 kg and radius 4.6 m is spinning about an axis through its center of mas

algol [13]

Answer:

6.3 rev/s

Explanation:

The new rotation rate of the satellite can be found by conservation of the angular momentum (L):

$L_{i} = L_{f}$

$I_{i}*\omega_{i} = I_{f}*\omega_{f}$

The initial moment of inertia of the satellite (a solid sphere) is given by:

$I_{i} = \frac{2}{5}m_{s}r^{2}$

Where $m_{s}$ : is the satellite mass and r: is the satellite's radium

$I_{i} = \frac{2}{5}m_{s}r^{2} = \frac{2}{5}1900 kg*(4.6 m)^{2} = 1.61 \cdot 10^{4} kg*m^{2}$

Now, the final moment of inertia is given by the satellite and the antennas (rod):

$I_{f} = I_{i} + 2*I_{a} = 1.61 \cdot 10^{4} kg*m^{2} + 2*\frac{1}{3}m_{a}l^{2}$

Where $m_{a}$ : is the antenna's mass and l: is the lenght of the antenna

$I_{f} = 1.61 \cdot 10^{4} kg*m^{2} + 2*\frac{1}{3}150.0 kg*(6.6 m)^{2} = 2.05 \cdot 10^{4} kg*m^{2}$

So, the new rotation rate of the satellite is:

$I_{i}*\omega_{i} = I_{f}*\omega_{f}$

$\omega_{f} = \frac{I_{i}*\omega_{i}}{I_{f}} = \frac{1.61 \cdot 10^{4} kg*m^{2}*8.0 \frac{rev}{s}}{2.05 \cdot 10^{4} kg*m^{2}} = 6.3 rev/s$

Therefore, the new rotation rate of the satellite is 6.3 rev/s.

I hope it helps you!

5 0

4 years ago

What is the relationship between mass and inertia? Give an example

ad-work [718]

Mass is that quantity that is solely dependent upon the inertia of an object. The more inertia that an object has, the more mass that it ha

5 0

3 years ago

A car travels west at 40 km/h

Nesterboy [21]

Answer:

The car is going 0 km/h more than the bike

Explanation:

3 0

3 years ago

Your goal is to accelerate the particles to kinetic energy k. what minimum radius r of the cyclotron is required?

densk [106]

Considering the magnetic force is providing the centripetal force,
we get, mv^2/r = qvB
so, r = mv/qB

as the Kinetic energy, K of the particle is given by.5mv^2
so, v = sqrt(2K/m)
substituting the in radius equation,
<span>r = m*sqrt(2K/m)/qB

r = sqrt(2Km)/qB</span>

4 0

4 years ago