Normal Force = 54 N
acceleration = 1.2 m/s^2
For Normal Force:
According to the force diagram, we can come up with the equation (all up and down forces):
10 sin 30 + Normal Force - 58.8 = 0
Normal Force = 53.8 N = 54 N
For acceleration:
According to the force diagram, we can come up with the equation (all left and right forces):
10 cos 30 - 1.5 = (6.0) (Acceleration)
Acceleration = 1.19 m/s^2 = 1.2 m/s^2
(d) Acceleration is a vector quantity
Line of code will call force with a value of 10 for mass and a value of 9.81 for acceleration is force(10, 9.81).
<h3 /><h3>Line of code for force and acceleration</h3>
- In mechanics, acceleration refers to the rate at which an object's velocity with respect to time varies.
- Acceleration is a vector quantity (in that they have magnitude and direction).
- The direction of an object's acceleration is determined by the direction of the net force acting on it.
- Newton's Second Law states that the combined effect of two factors determines how much an item accelerates.
- The size of the net balance of all external forces acting on the object is, in accordance with the materials used to create it.
- It inversely proportional to its mass, whereas the magnitude of the net resultant force is directly proportional to the net force.
def force(mass, acceleration):
force_val = mass*acceleration
return force_val
10 is assigned to mass and 9.81 is assigned to acceleration
def force(10, 9.81)
So, Line of code will call force with a value of 10 for mass and a value of 9.81 for acceleration is force(10, 9.81).
Learn more about acceleration here:
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1 nanowatt = 1 nanojoule/sec
1 watt = 1 joule/sec
10 watts = 10 joules/sec
100 watts = 100 joules/sec
742.914 watts = 742.914 joules/sec
1,000 watts = 1,000 joules/sec
10,000 watts = 10,000 joules/sec
100,000 watts = 100,000 joules/sec
1 megawatt = 1 megajoule/sec
1 gigawatt = 1 gigajoule/sec
1 petawatt = 1 petajoule/sec
We don't care what frequency the transmission is using,
or who their morning DJ is.
The velocity is 14 m/s
The parameters given on the question are
mass= 0.060 kg
kinetic energy= 5.9 joules
K.E= 1/2mv²
5.9= 1/2 × 0.060 × v²
5.9= 0.5 × 0.060v²
5.9= 003v²
v²= 5.9/0.03
v²= 196.66
v= √196.66
v= 14 m/s
Hence the velocity of the egg before it strikes the ground is 14 m/s
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