Answer:
m∠J = 45° , m∠I = 45° and m∠M = 90°
And the ΔJIM is an isosceles right angled triangle.
Step-by-step explanation:
(a). In ΔJIM,
∠J = 2x + 15,
∠I = 5x - 30, and
∠M = 6x
Now, using angle sum property of a triangle that sum of all the angles in a triangle is 180°
⇒ ∠J + ∠I + ∠M = 180°
⇒ 2x + 15 + 5x - 30 + 6x = 180°
⇒ 13x -15 = 180°
⇒ 13x = 195
⇒ x = 15
Therefore, m∠J = 45° , ∠I = 45° and m ∠M = 90°
(b). Now, ΔJIM is a right angled triangle right angled at M.
Also, ∠J = ∠I = 45°
So, JM = IM ( because in a triangle sides opposite to equal angles are equal)
So, ΔJIM is an isosceles triangle because its two sides are equal.
Hence, ΔJIM is a right angled isosceles triangle right angled at M.
Answer:
C
Step-by-step explanation:
Attachment
Answer:
![tan(450-a)=5\sqrt{3}-8](https://tex.z-dn.net/?f=tan%28450-a%29%3D5%5Csqrt%7B3%7D-8)
Step-by-step explanation:
We know that:
![tan(a-b)=\frac{tan(a)-tan(b)}{1+tan(a)tan(b)}](https://tex.z-dn.net/?f=tan%28a-b%29%3D%5Cfrac%7Btan%28a%29-tan%28b%29%7D%7B1%2Btan%28a%29tan%28b%29%7D)
![tan(450-a)=\frac{tan(450)-tan(a)}{1+tan(450)tan(a)}](https://tex.z-dn.net/?f=tan%28450-a%29%3D%5Cfrac%7Btan%28450%29-tan%28a%29%7D%7B1%2Btan%28450%29tan%28a%29%7D)
Remember:
450°=360°+60°
and:
![tan(a)=\frac{1}{2}](https://tex.z-dn.net/?f=tan%28a%29%3D%5Cfrac%7B1%7D%7B2%7D)
Thus:
![tan(450-a)=\frac{tan(60)-tan(a)}{1+tan(60)tan(a)}\\\\](https://tex.z-dn.net/?f=tan%28450-a%29%3D%5Cfrac%7Btan%2860%29-tan%28a%29%7D%7B1%2Btan%2860%29tan%28a%29%7D%5C%5C%5C%5C)
Then:
![tan(450-a)=5\sqrt{3}-8](https://tex.z-dn.net/?f=tan%28450-a%29%3D5%5Csqrt%7B3%7D-8)
Answer:
tree sampling: 2 1/4ft
through 1 year grown: 1 1/6ft
after two years growing: 5ft
1 1/6 coverted into a decimal is 0.16
0.16 x 32 = 5.12 (5)
not sure if this is right, but hope it helps