Ask question

Ask question

All categories

2 years ago

10

Henry bought a magazine for $5 and two vitamin waters. Henry spent a total of $11. How much did each vitamin water cost? $

2 answers:

saveliy_v [14]2 years ago

5 0

5+x=11
-5 -5
----------
x=6

vodka [1.7K]2 years ago

5 0

The Vitamin Water cost 3.00$ each

You might be interested in

PLEASE SOMEONE HELP ME ASAP!!!!!ANYONE PLEASE!!!!

Natasha2012 [34]

Answer: B.$43.95

Explanation: 15% of $293 is $43.95

6 0

2 years ago

Read 2 more answers

Which is the slope-intercept form of the equation of a line that passes through (5,-4) and has a slope of 3/4

Andreas93 [3]

Y = mx +b whre m is the slope and b is the y-intercept.

We have the slope 3/4 so put that instead of m

y = 3/4x + b

Now to find the y-intercept (b), plug the ordered pair in and solve for b.

-4 = 3/4 * 5 + b
-4 = 15/4 + b
-31/4 + b

So y = 3/4x - 31/4

4 0

3 years ago

Pls give me a real answer and not a link plsss fast

Scilla [17]

Answer:

1 solution

Step-by-step explanation:

the equation when distributed and simplified comes out to x=21

since there is only one variable there is only one answer

5 0

2 years ago

En un 9no grado, la asignatura de matemáticas la han aprobado el 62.5% de las alumnas y el 80% de los alumnos, mientras que la a

Paha777 [63]

Answer:

In the classroom there are 16 girls and 20 boys

Step-by-step explanation:

The question in English is

In the ninth grade, 62.5% of girls and 80% of boys passed the mathematics course, while 87.5% of girls and 60% of boys passed the history course. Calculate the number of students in the classroom, if the total number of passes is 26 in both subjects

Let

x ----> total girls in the classroom

y ---> total boys in the classroom

we know that

mathematics course

$0.625x+0.80y=26$ -----> equation A

history course

$0.875x+0.60y=26$ ----> equation B

Solve the system of equations by graphing

Remember that the solution is the intersection point both graphs

using a graphing tool

The solution is the point (16,20)

see the attached figure

therefore

In the classroom there are 16 girls and 20 boys

3 0

2 years ago

Estimate the indicated probability by using the normal approximation as an approximation to the binomial distribution. (PROBLEMS

S_A_V [24]

Answer:

4

$P(X \ge 219 ) = 0.093$

5

$P(X \ge 219 ) = 0.1038$

Step-by-step explanation:

From the question we are told that

The percentage of hair dryers that are defective is p=2% $= 0.02$

The sample size is $n =10000$

The random number is x = 219

The mean of this data set is evaluated as

$\mu = n* p$

substituting values

$\mu = 10000 * 0.02$

$\mu =200$

The standard deviation is evaluated as

$\sigma = \sqrt{[\mu (1 -p)]}$

substituting values

$\sigma = \sqrt{[200 (1 -0.02)]}$

$\sigma = 14$

Since it is a one tail test the degree of freedom is

df = 0.5

So

$x_l = x- 0.5$

$x = 219 - 0.5$

$x = 218.05$

Now applying normal approximation

$P(X \ge 219 ) = P(z > \frac{x - \mu}{\sigma} )$

substituting values

$P(X \ge 219 ) = P(z > \frac{218.5 - 200}{14} )$

$P(X \ge 219 ) = P(z > 1.32} )$

From the z-table

$P(X \ge 219 ) = 0.093$

Considering Question 5

The random number is x = 90

The mean is $\mu = n * p$

Where n = 100

and p = 0.85

So

$\mu = 0.85 *100$

$\mu = 85$

The standard deviation is evaluated as

$\sigma = \sqrt{[\mu (1 -p)]}$

substituting values

$\sigma = \sqrt{[85 (1 -0.85)]}$

$\sigma = 3.5707$

Since it is a one tail test the degree of freedom is

df = 0.5

Now applying normal approximation

$P(X \ge 90 ) = P(z > \frac{x - \mu}{\sigma} )$

substituting values

$P(X \ge 219 ) = P(z > \frac{89.5 - 85}{3.5707} )$

$P(X \ge 219 ) = P(z > 1.2603} )$

From the z-table

$P(X \ge 219 ) = 0.1038$

8 0

3 years ago