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guapka [62]
4 years ago
9

What forms as a result of the winds frictional force on water?

Chemistry
2 answers:
katrin [286]4 years ago
8 0

The correct answer is - waves.

The frictional force of the winds is the force with which the winds influence a surface. The smoother a surface is the lesser the friction, and vice versa. The water is a smooth surface, so the winds frictional force is not very big on it, but it is big enough to cause the occurrence of the waves. By constantly influencing the water with their frictional force the winds manage to move and disrupt the surface of the water, with the end result being the waves. Depending on the strength of the winds and the frictional force accordingly to that the waves can be very small, only few mm in height, or can be up to several meters in height.

worty [1.4K]4 years ago
5 0
<h2>Answer with Explanation </h2>

The outside of the Earth applies a frictional delay the air blowing simply above it. This grinding can act to alter the breeze's course and moderate it down shielding it from blowing as quick as the breeze up high. All things considered, the distinction in territory conditions straightforwardly influences how much grinding is applied. For instance, a quiet sea surface is truly smooth, so the breeze blowing over it doesn't climb, down, and around any highlights.

<h2>Answer 2 with Explanation </h2>

On the other hand, slopes and woodlands compel the breeze to back off or potentially alter course considerably more. As we move higher, surface highlights influence the breezeless until the breeze is surely geostrophic. This dimension is viewed as the highest point of the limit (or grinding) layer. The stature of the limit layer can shift contingent upon the sort of territory, wind, and vertical temperature profile. The season of day and period of the year additionally influence the stature of the limit layer. Be that as it may, for the most part, the limit layer exists from the surface to around 1-2 km above it.

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3 years ago
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Question one should be obvious..

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The pressure inside a pressure cooker is 2.0 atm. How many minutes will it take to cook 1.0 pound of potatoes in a pressure cook
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3 years ago
A solution is prepared by dissolving 15.0 g of nh3 in 250.0 g of water. the density of the resulting solution is 0.974 g/ml. the
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To solve this problem, first we assume the volume is purely additive. The density of the mixture can then be calculated by the summation of mass fraction of each component divided by its individual density:

1 / ρ mixture = (x NH3 / ρ NH3) + (x H2O / ρ<span> H2O)                        ---> 1</span>

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x NH3 = 0.0566

Therefore the mass fraction of water is:

x H2O = 1 – x NH3 = 1 – 0.0566

x H2O = 0.9434

Assuming that the density of water is 1 g / mL and substituting the known values back to equation 1:

1 / 0.974 g / mL = [0.0566 / (ρ NH3)] + [0.9434 / (1 g / mL)]

ρ NH3 = 0.680 g / mL

Given the density of NH3, now we can calculate for the volume of NH3:

V NH3 = 15 g / 0.680 g / mL

V NH3 = 22.07 mL

The number of moles NH3 is: (molar mass NH3 is 17.03 g / mol)

n NH3 = 15 g / 17.03 g / mol

n NH3 = 0.881 mol

Therefore the molarity of NH3 in the solution is:

<span>Molarity = 0.881 mol / [(22.07 mL  + 250 mL) * (1L / 1000 mL)</span>

<span>M = 3.238 mol/L = 3.24 M</span>

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3 years ago
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