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gavmur [86]
3 years ago
13

How many atoms of phosphorus are in 4.90 mol of copper(II) phosphate?

Chemistry
1 answer:
Nutka1998 [239]3 years ago
8 0
There are  6.02214*10^23 molecules , I'm not so sure about it though.
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Assume that 8.5 L of iodine gas (I2) are produced at STP according to the following balanced equation:2KI(aq) + Cl2(
Aliun [14]

Answer: 0.3794 moles of Iodine gas are produced.

Explanation:

2KI(aq)+Cl_2(
g)\rightarrow 2KCl(aq)+I_2

Volume of iodine gas produced at STP =8.5 L

At STP, the 1 mol of gas occupies volume = 22.4 L

So, 8.5 L of volume will be occupied by:\frac{1}{22.4 L}\times 8.5=0.3794 moles

0.3794 moles of Iodine gas are produced.

5 0
3 years ago
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What is the formula for the compound formed by lead(lV) ions and chromate ions
nexus9112 [7]

Answer:

Lead (IV) Chromate: Pb(CrO4)2

Explanation:

8 0
3 years ago
Given the following, determine ΔG°f at 298 K for SnO. Sn(s) + SnO2(s) → 2SnO(s) ; ΔG° = 12.0 kJ at 298K
Virty [35]

Answer:

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Explanation:

Sn(s) + SnO_2(s)\rightarrow 2SnO(s), \Delta G_{f}^{o} = 12.0 kJ

\Delta G_{f,SnO_2}^{o}= -515.8kJ/mol

\Delta G_{f,Sn}^{o}= 0 kJ/mol

\Delta G_{f,SnO}^{o}=?

\Delta G_{f}^{o}=\sum ((\Delta G_{f}^{o})_ {products})-\sum ((\Delta G_{f}^{o})_ {reactants})

12.0 kJ=(2 mol\times \Delta G_{f,SnO}^{o})-(1mol\times 0 kJ/mol+1 mol\times -515.8 kJ/mol)

\Delta G_{f,SnO}^{o}=-251.9 kJ/mol

The value of change in Gibbs free energy for tin(II) oxide solid is -251.9 kJ/mol.

3 0
3 years ago
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Easy just convert it to feet the answer is <span>1113.51706 Feet

</span>
6 0
3 years ago
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uranmaximum [27]

ANSWER

Find the attachment

7 0
3 years ago
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