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Reika [66]
3 years ago
12

Cattle are likely to become highly agitated when separated from their herdmates.

Physics
1 answer:
Nataly [62]3 years ago
3 0

Answer:

true

Explanation:

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Bonsoir pouvez vous m'aider svp.<br>Mathématiques
LenaWriter [7]

bonsoir, je peux vous aider avec les maths laissez-moi comprendre merci

4 0
3 years ago
What is the definition of Cubit
disa [49]

Answer:

See below.

Explanation:

Cubit is a unit of length based on the length of the forearm from the elbow to the tip of the middle finger and usually equal to about 18 inches (46 centimeters).

It is an ancient unit of length used in ancient Egypt and is also known as "ancient Egyptian royal cubit."

Other similar units of measurements are displayed in the image below. Thanks!

7 0
2 years ago
A thin film of soap with n = 1.34 hanging in the air reflects dominantly red light with λ = 642 nm. What is the minimum thicknes
wariber [46]

Answer:

The minimum thickness of the film and the wavelength of the light in air are 1.197\times10^{-7}\ m and 371 nm.

Explanation:

Given that,

Refractive index of soap= 1.34

Refractive index  of glass= 1.55

Wavelength = 642 nm

(I). We need to calculate the minimum thickness

Using formula of thickness

t=\dfrac{(2m+1)\lambda}{4n}

Where, m = 0 for constrictive

Put the value into the formula

t=\dfrac{(642\times10^{-9})}{4\times1.34}

t=1.197\times10^{-7}\ m

(II). We need to calculate the wavelength

Using formula of wavelength

\lambda=\dfrac{2nt}{m}

Where, m = 1

Put the value into the formula

\lambda=\dfrac{2\times1.55\times1.197\times10^{-7}}{1}

\lambda=371\ nm

Hence, The minimum thickness of the film and the wavelength of the light in air are 1.197\times10^{-7}\ m and 371 nm.

6 0
3 years ago
……………………………………………………………..?
TEA [102]

Answer:

last is the answer.

increase the voltage in order to send energy faster.

4 0
2 years ago
A 3.0 \Omega Ω resistor is connected in parallel to a 6.0 \Omega Ω resistor, and the combination is connected in series with a 4
GarryVolchara [31]

Answer:

The power dissipated in the 3 Ω resistor is P= 5.3watts.

Explanation:

After combine the 3 and 6 Ω resistor in parallel, we have an 2 Ω and a 4 Ω resistor in series.

The resultating resistor is of Req=6Ω.

I= V/Req

I= 2A

the parallel resistors have a potential drop of Vparallel=4 volts.

I(3Ω) = Vparallel/R(3Ω)

I(3Ω)= 1.33A

P= I(3Ω)² * R(3Ω)

P= 5.3 Watts

7 0
3 years ago
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