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s2008m [1.1K]
2 years ago
8

A car accelerates at a constant rate of 3 m/s2 for 5 seconds. If it reaches a velocity of 27 m/s, what was its initial velocity?

Physics
1 answer:
Kaylis [27]2 years ago
4 0

The initial velocity of a car that accelerates at a constant rate of 3m/s² for 5 seconds is 12m/s.

CALCULATE INITIAL VELOCITY:

The initial velocity of the car can be calculated by using one of the equation of motion as follows:

V = u + at

Where;

  • V = final velocity (m/s)
  • u = initial velocity (m/s)
  • a = acceleration due to gravity (m/s²)
  • t = time (s)

According to this question, a car accelerates at a constant rate of 3 m/s² for 5 seconds. If it reaches a velocity of 27 m/s, its initial velocity is calculated as follows:

u = v - at

u = 27 - 3(5)

u = 27 - 15

u = 12m/s.

Therefore, the initial velocity of a car that accelerates at a constant rate of 3m/s² for 5 seconds is 12m/s.

Learn more about motion at: brainly.com/question/974124

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Answer:

P=3.42×10^-6 J/s

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so,

vf^2 =vi^2+2*a(xf-xi)

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now we can use the power P Eq.  

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P=1/2*m*vf^2-1/2*m*vi^2/Δt

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