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e-lub [12.9K]
3 years ago
10

Covalent compounds are usually described as

Physics
1 answer:
topjm [15]3 years ago
8 0

Explanation:

Another name of covalent bonds is molecular bonds. Covalent compounds are formed by covalent bonds. The bonds in which atoms share one of more valance electrons are termed as covalent bonds. These types of bonds are in Liquid or gaseous State.

For example, methane is a covalent compound that is formed by the sharing of electrons between carbon and hydrogen atoms. Hence, Covalent compounds are usually described as the sharing of electrons between carbon atoms

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As you travel from Detroit in a certain direction, the outside temperature, T (in degrees), depends on your distance, d (in mile
Ber [7]

Answer:

a)\Delta T= 100^{\circ}C

b)\bigtriangledown T=1^{\circ}C.mile^{-1}

c)\bigtriangledown T_4=1^{\circ}C.mile^{-1}

d)\bigtriangledown T_4=1^{\circ}C.mile^{-1}

Explanation:

Given is the data of variation of temperature with respect to the distance traveled:

Temperature T as a function of distance d:

T=(d+30) ^{\circ}C...................................(1)

(a)

Total change in temperature from the start till the end of the journey:

\Delta T= T_f-T_i..............................(2)

where:

T_f= final temperature

T_i= initial temperature

∵In the start of the journey d = 0 miles & at the end of the journey d = 100 miles.

So, correspondingly we have the eq. (2) & (1) as:

\Delta T= (100+30)-(0+30)

\Delta T= 100^{\circ}C

(b)

Now, the average rate of change of the temperature, with respect to distance, from the beginning of the trip to the end of the trip be calculated as:

\bigtriangledown T=\frac{\Delta T}{\Delta d}......................(3)

where:

\Delta d= change in distance

\bigtriangledown T=change in temperature with respect to distance

putting the respective values in eq. (3)

\bigtriangledown T=\frac{100}{100}

\bigtriangledown T=1^{\circ}C.mile^{-1}

(c)

comparing the given function of the temperature with the general equation of  a straight line:

y=m.x+c

We find that we have the slope of the equation as 1 throughout the journey and therefore the rate of change in temperature with respect to distance remains constant.

\bigtriangledown T_4=1^{\circ}C.mile^{-1}

(d)

comparing the given function of the temperature with the general equation of  a straight line:

y=m.x+c

We find that we have the slope of the equation as 1 throughout the journey and therefore the rate of change in temperature with respect to distance remains constant.

\bigtriangledown T_4=1^{\circ}C.mile^{-1}

4 0
4 years ago
A wave that travels through matter is called a(n) _____ wave.
vlabodo [156]

Answer:    longitudinal wave is a type of mechanical wave, or wave that travels through matter, called the medium.

Explanation:

7 0
3 years ago
Read 2 more answers
displacement vectors of 4 km south, 2 km north, 5 km south, and 5 km north combine to a total displacement of a. 16 km north b.
den301095 [7]
I think the answer is 2 km south. This is because when someone moves 4km south and moves 2km north, the final position 2km south. and if the person moves 5 km farther north,the position is now 3km north and if he moves 5km south, the final position is 2km south.
5 0
3 years ago
A point charge q1 is held stationary at the origin. A second charge q2 is placed at point a, and the electric potential energy o
Brrunno [24]

The electric potential energy of the pair of charges when the second charge is at point b is 7.3 x 10⁻⁸ J.

<h3>Electric potential energy</h3>

When work is done on a positive test charge to move it from one location to another, potential energy increases and electric potential increases.

The electric potential energy between the charges when the second charge is at point b is calculated as follows;

ΔU = -w

Ui - Uf = w

Uf = Ui - w

where;

Uf is the final potential energy

Ui is the initial potential energy

w is the work done by the force

Uf = 5.4 x 10⁻⁸ J - (-1.9 x 10⁻⁸J)

Uf = 5.4 x 10⁻⁸ J + 1.9 x 10⁻⁸ J

Uf = 7.3 x 10⁻⁸ J

Thus, the electric potential energy of the pair of charges when the second charge is at point b is 7.3 x 10⁻⁸ J.

Learn more about electric potential energy here: brainly.com/question/14306881

#SPJ1

7 0
2 years ago
An electron collides elastically with a stationary hydrogen atom. The mass of the hydrogen atom is 1837 times that of the electr
tamaranim1 [39]

Answer:

\frac{K_{h}}{K_{i}} = = 2.17 \times 10^{-3}

Explanation:

As we know that there is no external force on the system of hydrogen atom and electron so we will say momentum is conserved

so we will have

m_1 v_{1i} = m_1v_{1f} + m_2v_{2f}

here we know that

m_1 = m

m_2 = 1837m

now we have

m v = mv_{1f} + 1837v_{2f}

v_{1f} + 1837v_{2f} = v

also we know that

v_{2f} - v_{1f} = v

now we will have

1838v_{2f} = 2v

v_{2f} = \frac{v}{919}

now we need to find the ratio of kinetic energy of hydrogen atom with initial kinetic energy

so it is given as

\frac{K_{h}}{K_{i}} = \frac{\frac{1}{2}(1837m)(\frac{v}{919})^2}{\frac{1}{2}mv^2}

\frac{K_{h}}{K_{i}} =\frac{1837}{919^2}

\frac{K_{h}}{K_{i}} = = 2.17 \times 10^{-3}

4 0
4 years ago
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