The answer is going to be element #29 Copper makes blue
Red:#38
Green:#56
Pink:#3
Yellow:#11
Gold:#20
Hopes This Helps
Answer:
4. Personnel policies and programs
Explanation:
The Health care organizations that apply for Magnet status must demonstrate new ways of doing things and innovations in professional practice.
Personnel policies and programs is one of the forces of magnetism that impacts the structural empowerment of the organization.
The Personnel policies of an organization should provide an innovative environment in which the staff are developed and empowered. Empirical quality outcomes are reviewed by assessing the quality of care. New knowledge, innovations, and improvements are reviewed by assessing the quality improvement of the health care organization. Interdisciplinary relationships are assessed to review exemplary professional practice.
Answer:
As, Jupiter are one of the largest planet in the solar system and the large amount of the mass of the jupiter are consisted with the gases. The storm tracks in the symmetrical path at the proper latitude in the system. But the storm tracks on the earth in the system where planet are highly variable.
Answer:
T = 1.12 10⁻⁷ s
Explanation:
This exercise must be solved in parts. Let's start looking for the electric field in the axis of the ring.
All the charge dq is at a distance r
dE = k dq / r²
Due to the symmetry of the ring, the field perpendicular to the axis is canceled, leaving only the field in the direction of the axis, if we use trigonometry
cos θ =
dEₓ = dE cos θ
cos θ = x / r
substituting
dEₓ =
DEₓ = k dq x / r³
let's use the Pythagorean theorem to find the distance r
r² = x² + a²
where a is the radius of the ring
we substitute
dEₓ =
we integrate
∫ dEₓ =k \frac{x}{(x^2 + a^2 ) ^{3/2} } ∫ dq
Eₓ = 
In the exercise indicate that the electron is very central to the center of the ring
x << a
Eₓ =
if we expand in a series
we keep the first term if x<<a
Eₓ =
the force is
F = q E
F = 
this is a restoring force proportional to the displacement so the movement is simple harmonic,
F = m a
the solution is of type
x = A cos (wt + Ф)
with angular velocity
w² =
angular velocity and period are related
w = 2π/ T
we substitute
4π² / T² = \frac{keQ}{m a^3}
T = 2π
let's calculate
T = 2π
T = 2π pi 
T = 2π 17.9 10⁻⁹ s
T = 1.12 10⁻⁷ s