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e-lub [12.9K]
2 years ago
15

What is the hardest stage of BME​

Physics
2 answers:
dexar [7]2 years ago
5 0

Answer:

Medical software generation

san4es73 [151]2 years ago
3 0

Answer:

Neural Engineering and Tissue Engineering

Explanation:

• BME is Biomedical Engineering. It has various topics such as Anantomy, Physiology, Neural Engineering and Tissue engineering, Medical mechanisation and others.

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if you wanted to increase the energy of a wave but you had to leave the wavelength the same what might you do ​
Blizzard [7]

Answer:

Increase the amplitude

Explanation:

The energy conveyed by a wave is directly proportional to the square of its amplitude. Thus; E ∝ A²

This means that increasing the amplitude will lead to an increase in the energy.

Now, the amplitude of a wave is the height of a wave from it's highest point known as the peak, to the lowest point on the wave known as the trough whereas wavelength refers to the length of a wave from one peak to the next.

This means that increasing the amplitude has no effect on the wavelength.

7 0
3 years ago
The energy of a photon of light is ________ proportional to its frequency and ________ proportional to its wavelength.
nirvana33 [79]
The energy of a photon of light is directly proportional to its frequency and <span>inversely</span> proportional to its wavelength.
7 0
3 years ago
Batteries are usually identified by their voltage.
Fynjy0 [20]

Answer:

Explanation:

Given parameters:

Electrical energy  = 18J

Quantity of charge Q = 12C

Unknown:

Voltage  = ?

Solution:

The expression of electrical potential energy is given as:

      Electrical potential energy  = \frac{1}{2} c v²

c is the quantity of charge

v is the voltage

           18  =  \frac{1}{2}  x 12 x v²  

           18 = 6v²  

              v² = 3  

               v = 1.7v

7 0
3 years ago
Calculate the angular velocity of the neptune (orbital period of 165 earth period) in its orbit around the sun.
ludmilkaskok [199]
The correct answer is: Angular velocity =  1.208 * 10^{-9} rad/s

Explanation:
The angular velocity is given as:
ω = \frac{2\pi}{T} --- (1)

Where T = 165 * (365 days) * (24 hours/day) * (60 minutes/hour) * (60 seconds/minute) = 5203440000 s

Plug in the value in (1):
ω = \frac{2\pi}{5203440000} = 1.208 * 10^{-9} rad/s
7 0
3 years ago
A snowmobile moves according to the velocity-time graph shown in the drawing. What is the snowmobile's average acceleration duri
Anit [1.1K]

Answer:

(a). The average acceleration during segment A is 2 m/s²

(b). The average acceleration during segment B is zero.

(c). The average acceleration during segment C is 4 m/s².

Explanation:

Given that,

A snowmobile moves according to the velocity-time graph ,

(a), We need to calculate the average acceleration during segment A

Using formula of average acceleration

a=\dfrac{v_{f}-v_{i}}{t_{2}-t_{1}}

Where, v_{i} = initial velocity

v_{f} =final velocity

t_{i} = initial time

t_{f} =final time

Put the value into the formula

a=\dfrac{40-0}{20-0}

a=2\ m/s^2

(b). We need to calculate the average acceleration during segment B

Using formula of average acceleration

a=\dfrac{v_{f}-v_{i}}{t_{2}-t_{1}}

Put the value into the formula

a=\dfrac{40-40}{50-20}

a=0\ m/s^2

(c). We need to calculate the average acceleration during segment C

Using formula of average acceleration

a=\dfrac{v_{f}-v_{i}}{t_{2}-t_{1}}

Put the value into the formula

a=\dfrac{80-40}{60-50}

a=4\ m/s^2

Hence, (a). The average acceleration during segment A is 2 m/s²

(b). The average acceleration during segment B is zero.

(c). The average acceleration during segment C is 4 m/s².

4 0
4 years ago
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