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3 years ago

Approximate the square root of 500 to the nearest tenth. Show your work.

1 answer:

4 0

$\sqrt{500} \rightarrow \sqrt{5 * 10 * 10} \rightarrow 10\sqrt{5}$ This is an exact answer. the answer will be a bit larger than 20

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What is the value of x in the equation shown? 2(X + 8) - 4x = 10x + 4

Anna007 [38]

Answer:

Option C: X=1

Step-by-step explanation:

2(X + 8) - 4x = 10x + 4

2X + 16- 4X= 10X + 4

-2X +16 =10X + 4

16 - 4 = 10X+2X

12 =12X

X=1

7 0

2 years ago

Alex has a rectangle piece of red paper that is 4 centimeter wide .its length is twice it's width she glues a piece of paper blu

xenn [34]

4cm•2=8cm which is the length of the red paper so therefore Red paper= 4cmx8cm.
Then your going to take 3cm-4cm= 1cm
Next your going to solve for 7cm-8cm=1cm
Which leaves you with an answer of 1cmx1cm more of visible red paper.

8 0

3 years ago

Which of the following statements is true of a transversal?

kolbaska11 [484]

Answer:

The answer here is the third box(C)

I hope this helps you!

3 0

2 years ago

g If the economy improves, a certain stock stock will have a return of 23.4 percent. If the economy declines, the stock will hav

dusya [7]

Answer:

$E(X) = 23.4* 0.67 -11.9*0.33= 11.759 \%$

Now we can find the second central moment with this formula:

$E(X^2) = \sum_{i=1}^n X^2_i P(X_i)$

And replacing we got:

$E(X^2) = (23.4)^2* 0.67 +(-11.9)^2*0.33= 413.5965$

And the variance is given by:

$Var(X) = E(X^2) - [E(X)]^2$

And replacing we got:

$Var(X) = 413.5965 -(11.759)^2 =275.5105$

And finally the deviation would be:

$Sd(X) = \sqrt{275.5105}= 16.599 \%$

Step-by-step explanation:

We can define the random variable of interest X as the return from a stock and we know the following conditions:

$X_1 = 23.4 , P(X_1) =0.67$ represent the result if the economy improves

$X_2 = -11.9 , P(X_1) =0.33$ represent the result if we have a recession

We want to find the standard deviation for the returns on the stock. We need to begin finding the mean with this formula:

$E(X) = \sum_{i=1}^n X_i P(X_i)$

And replacing the data given we got:

$E(X) = 23.4* 0.67 -11.9*0.33= 11.759 \%$

Now we can find the second central moment with this formula:

$E(X^2) = \sum_{i=1}^n X^2_i P(X_i)$

And replacing we got:

$E(X^2) = (23.4)^2* 0.67 +(-11.9)^2*0.33= 413.5965$

And the variance is given by:

$Var(X) = E(X^2) - [E(X)]^2$

And replacing we got:

$Var(X) = 413.5965 -(11.759)^2 =275.5105$

And finally the deviation would be:

$Sd(X) = \sqrt{275.5105}= 16.599 \%$

7 0

2 years ago

Find the slope of the line that passes through (-61, 3) and (-41, 31)

Alexus [3.1K]

Answer:

im pretty sure its 1.4

Step-by-step explanation:

3 0

2 years ago