Calculate the ratio by using Henderson-Hasselbalch equation:
pH = pKa + log [neutral form] / Protonated form
3.05 = 2.21 + log [neutral form] / [Protonated form]
3.05 - 2.21 = log [neutral form] / [Protonated form]
0.84 = log [neutral form] / [Protonated form]
[neutral form] / [protonated form] = anti log 0.84 = 6.91
The monochloroderivatives will be obtained by substituting chemically non equivalent hydrogen with chlorine atom, one by one
So the possible monochloro derivatives of 2,4-dimethylpentane (figure 1) are shown in figure (2)
Answer:
P₂ = 28.5 torr
Explanation:
Given data:
Initial pressure = 38 torr
Initial volume = 500 L
Final volume = 677 L
Final pressure = ?
Solution:
P₁V₁ = P₂V₂
P₁ = Initial pressure
V₁ = Initial volume
P₂ = Final pressure
V₂ = Final volume
Now we will put the vales in formula.
P₁V₁ = P₂V₂
P₂ = P₁V₁ /V₂
P₂ = 38 torr × 500 L / 667 L
P₂ = 19000 torr. L / 667 L
P₂ = 28.5 torr
Answer:
Calculate the pH of 0.010 M HNO2 solution. The K, for HNO2 is 4.6 x 104
Answer: pH = 2.72
Answer:
65.21 percent
Explanation:
We are to find the percentage yield
We have this equation,
2no+o2 -->2no2
Such that 1500 kilograms/30grams
= Mno2/46
=1500/30 = mno2/46
We cross multiply from here
1500x46 = 30xMnO2
69000 = 30Mno2
69000/30 = MnO2
2300 = Mno2
The percentage yield would be
1500/2300 *100
= 0.6521 x 100
= 65.21%
This answers the question
