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mezya [45]
3 years ago
6

a hot air balloon has a volume of 875L. what is the original temperature of the balloon if its volume changes to 955 L when heat

ed to 56
Chemistry
1 answer:
soldi70 [24.7K]3 years ago
4 0

Answer:

using Charles law

v1/t1= v2/ t2

Explanation:

875/t1=955/56+273

t1= 329* 875/955

t1= 302.82k

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A container holds three gases: oxygen, carbon dioxide, and helium. The partial pressures of the three gases are 2.00 atm, 3.00 a
Elan Coil [88]

Answer:

9.00 atm

For total pressure, you would add all the pressures together

7 0
3 years ago
Mrs. Borunda has a sample of oxygen gas that occupies a volume of 600 L at 400 atm pressure. What will the pressure be if she in
kotykmax [81]

Answer:

P₂ = 300 atm

Explanation:

Given that,

Initial volume, V₁ = 600 L

Initial pressure, P₁ = 400 atm

We need to find the pressure if the volume is 800 L.

We know that the relation between pressure and volume is given by :

P\propto \dfrac{1}{V}\\\\\dfrac{P_1}{P_2}=\dfrac{V_2}{V_1}\\\\P_2=\dfrac{P_1V_1}{V_2}\\\\P_2=\dfrac{600\times 400}{800}\\\\P_2=300\ atm

So, the new pressure is equal to 300 atm.

5 0
3 years ago
A 20. 0-liter flask contains a mixture of argon at 0. 72 atmosphere and oxygen at 1. 65 atmospheres. What is the total pressure
exis [7]

The total pressure of the system is equivalent to the sum of all the pressure of the individual gases. The total pressure of the flask is 2.37 atm.

<h3>What is total pressure?</h3>

According to Dalton's law, the total pressure of the system will be equivalent to the total of the pressures exerted by the individual gases present in the system.

The total pressure of gases is given as,

\rm P = P_{1} +P_{2}+ P_{3}.....P_{n}

Given,

  • The pressure of argon gas = 0.72 atm
  • The pressure of oxygen = 1.65 atm
  • Total pressure = P

Substituting values in the above equation:

\begin{aligned}\rm P &= 0.72 + 1.65\\\\&=2.37\;\rm atm\end{aligned}

Therefore, 2.37 atm is the total pressure of the flask.

Learn more about total pressure here:

brainly.com/question/11150092

5 0
3 years ago
Using a 300 MHz NMR instrument:
Softa [21]

Answer:

a. 750Hz, b. 4.0ppm, c. 600Hz

Explanation:

The Downfield Shift (Hz) is given by the formula

Downfield Shift (Hz) = Chemical Shift (ppm) x Spectrometer Frequency (Hz)

Using the above formula we can solve all three parts easily

a. fspec = 300 MHz, Chem. Shift = 2.5ppm, 1MHz = 10⁶ Hz, 1ppm (parts per million) = 10⁻⁶

Downfield Shift (Hz) = 2.5ppm x 300MHz x (1Hz/10⁶MHz) x (10⁻⁶/1ppm)

Downfield Shift = 750 Hz

The signal is at 750Hz Downfield from TMS

b. Downfield Shift = 1200 Hz, Chemical Shift = ?

Chemical Shift = Downfield shift/Spectrometer Frequency

Chemical Shift = (1200Hz/300MHz) x (1ppm/10⁻⁶) = 4.0 ppm

The signal comes at 4.0 ppm

c. Separation of 2ppm, Downfield Shift = ?

Downfield Shift (Hz) = 2(ppm) x 300 (MHz) x (1Hz/10⁶MHz) x (10⁻⁶/1ppm) = 600 Hz

The two peaks are separated by 600Hz

6 0
3 years ago
Number of moles in 37g of magnesium​
Ne4ueva [31]
Rounded its 1.522 mol
3 0
3 years ago
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