I need help with number two too?

Chemistry

1 answer:

KIM [24]3 years ago

8 0

1. 20s, 22s, and 30s... height is the highest.

2. 34s, 38s, and 41s..... height is at its lowest.

i could be wrong.... but i tried.

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How is the rate of appearance of h2o related to the rate of disappearance of o2?

erastovalidia [21]

If we consider a combustion reaction of Methane:

The balanced equation is:

CH4 + 2O2 ---> 2H2O + CO2

The rate of appearance of H2O is rH2O, rate of disappearance of O2 is -rO2

(rH2O)^2 = (-rO2)^2
rH2O = -rO2

6 0

3 years ago

PLEASE HELP

n200080 [17]

Mk i will comment so u can make them brainliest lols

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3 years ago

Read 2 more answers

Write the rates for the following reactions in terms of the disappearance of reactants and appearance of products: (a) 302 .....

Oduvanchick [21]

Answer:

Explanation:

$\mathbf{From \ the \ information \ given:} \\ \\ \mathbf{The \ rates \ of \ the \ f ollowing \ reactions \ can \ be \ expressed \ as \ follows:}$

(a)

$\mathbf{3O_2 \to 2O_3} \\ \\ \\ \mathbf{-\dfrac{1}{3}\dfrac{d[O_2]}{dt}=\dfrac{2}{3} \dfrac{d[O_3]}{dt}}$

(b)

$\mathbf{C_2H_6 \to C_2H_4 + H_2} \\ \\ \\ \mathbf{ -\dfrac{d[C_2H_6]}{dt}= \dfrac{d[C_2H_4]}{dt}=\dfrac{d[H_2]}{dt}}$

(c)

$\mathbf{ClO^-+Br^- \to BrO^-+Cl^-} \\ \\ \\ \mathbf{ -\dfrac{d[ClO^-]}{dt}= -\dfrac{d[Br^-]}{dt} = \dfrac{d[BrO^-]}{dt} = \dfrac{d[Cl^-]}{dt} }$

(d)

$\mathbf{(CH_3)_3 CCl+H_2O \to (CH_3)_3COH + H^+ + Cl^-} \\ \\ \\ \mathbf{- \dfrac{d[(CH_3)_3CCl}{dt}= - \dfrac{d[H_2O]}{dt}= \dfrac{d[CH_3)_3COH}{dt}= \dfrac{d[H^+]}{dt}= \dfrac{d[Cl^-]}{dt}}$