3 years ago

. What is the mass, in grams, of a sample of 7.83 × 1024 atoms of helium (He)?

Chemistry

1 answer:

erica [24]3 years ago

6 0

Moles He = 7.83 x 10^24 / 6.02 x 10^23 =13.0

<span>mass He = 13.0 mol x 4.00 g/mol = 52.0 g</span>

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Solution :

A cell that is concentrated is constructed by the same half reaction for the anode as well as he cathode.

We know,

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the reduction half cell reaction is :

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2 years ago

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Answer:

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2 years ago

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3 years ago

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mezya [45]

Answer:

Rock

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Rock:

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2 years ago

How many grams of carbon (C) would be present in carbon monoxide (CO) that contains 2.666 grams of oxygen (O)? For example if th

oee [108]

Given :

Mass of oxygen containing carbon monoxide (CO) is 2.666 gram .

To Find :

How many grams of carbon (C) would be present in carbon monoxide (CO) that contains 2.666 grams of oxygen (O) .

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So , volume of solution does not matter .

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Now , molecule of CO contains 1 mole of C .

So , moles of C is also 0.167 mole .

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2 years ago