Question

an eskimo pushes a loaded sled with a mass of 300kg over the frictionless surface of hard-packed snow.he exerts a constant 170n force as he dose so.what is the sled's acceleration?

Answer 1

Answer:

The sled's acceleration is $\vec{a}=0,57\frac{m}{s^{2}}\hat{x}$ .

Explanation:

Newton's second law of motion states that in an inertial frame of reference the net force $\vec{F}$ acting on an object is equal to the mass m of the object multiplied by its acceleration $\vec{a}$:

                                                   $\vec{F}=m\vec{a}$

$\vec{F}$ and $\vec{a}$ are vectors and the mass m is a scalar that we assume to be constant. We also assume that the net force $\vec{F}$ and the acceleration $\vec{a}$ are in the horizontal direction x.

We are told that |F| = 170 N and that m = 300 kg. So we get that:

                                               $170N=300kg\ a$

                                               $170\frac{kg\ m}{s^{2}}=300kg\ a$

                                               $a=\frac{170}{300} \frac{kg\ m}{s^{2}} \frac{1}{kg}$

                                               $a=0,57\frac{m}{s^{2}}$

Then the sled's acceleration is

                                               $\vec{a}=0,57\frac{m}{s^{2}}\hat{x}$

                                               

                                             

Answer 2

Answer:

0.567 m/s²

Explanation:

Newton's second law:

∑F = ma

170 N = (300 kg) a

a = 0.567 m/s²

Round as needed.