Answer:
F = 2,894 N
Explanation:
For this exercise let's use Newton's second law
F = m a
The acceleration is centripetal
a = v² / r
Angular and linear variables are related.
v = w r
Let's replace
F = m w² r
The radius r and the length of the rope is related
cos is = r / L
r = L cos tea
Let's replace
F = m w² L cos θ
Let's reduce the magnitudes to the SI system
m = 101.7 g (1 kg / 1000g) = 0.1017 kg
θ = 5 rev (2π rad / rev) = 31,416 rad
w = θ / t
w = 31.416 / 5.1
w = 6.16 rad / s
F = 0.1017 6.16² 0.75 cos θ
F = 2,894 cos θ
The maximum value of F is for θ equal to zero
F = 2,894 N
As we know,

so, let's solve for charge (q) :
time = 5 minutes = 5 × 60 seconds = 300 seconds.
hence, the charge = 60 coulombs (C)
Answer:
The answer is
<h2>84.9 kPa</h2>
Explanation:
Using Boyle's law to find the final pressure
That's

where
P1 is the initial pressure
P2 is the final pressure
V1 is the initial volume
V2 is the final volume
Since we are finding the final pressure

From the question
P1 = 115 kPa
V1 = 480 mL
V2 = 650 ml
So we have

We have the final answer as
<h3>84.9 kPa</h3>
Hope this helps you
Answer:
The period of a mass m on a spring of spring constant k can be calculated as T=2π√mk T = 2 π m k .
Explanation: