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kati45 [8]
3 years ago
7

An object will have the same mass and weight on the moon as it has on Earth.

Physics
1 answer:
Ber [7]3 years ago
6 0

Answer: A: false

Explanation:

And object will weigh less on the moon because the moons gravity is weaker than Earths gravity.

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How to solve the problem
erica [24]
If you're looking for distance, you have to multiply the time and speed.

0.75 × 45 = 33.75

The rabbit hopped 33.75 m.
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Why does a geostationary satellite must orbit around Earth's equator, rather than in some other orbit (such as around the poles)
LiRa [457]

Answer:

A satellite on non-equatorial orbit would show daily motion even if its period is exactly 1 sidereal day.

Explanation:

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2 years ago
wildlife biologists are working to save some unique birds in the forest of north georgia.which of these questions must be answer
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7 0
3 years ago
A weight lifter is trying to do a bicep curl with a weight of 300 N. At the "sticking point", the moment arm of this weight is 3
lesantik [10]

Answer:

The weight lifter would not get past this sticking point.

Explanation:

Generally torque applied on the weight is mathematically represented as

             T =  F z

To obtain Elbow torque we substitute 4000 N for F (the force ) and 2cm = \frac{2}{100} = 0.02m for z the perpendicular distance

So Elbow Torque is   T_e= 4000 * 0.02

                                   = 80Nm

 To obtain the torque required we substitute 300 N for F and 30cm =\frac{30}{100} = 0.3 m

  So the Required Torque is T_R = 300 *0.3

                                                     =90Nm

Now since   T_e < T_R it mean that the weight lifter would not get past this sticking point

                                   

7 0
3 years ago
12. A car is travelling at 30 m/s when the driver sees a red light in the distance and immediately applies the brakes. The car c
Triss [41]

Answer:

22.5 m

Explanation:

From the question given above, the following data were obtained:

Initial velocity (u) = 30 m/s

Time (t) = 1.5 s

Final velocity (v) = 0 m/s

Distance (s) =?

The distance to which the car move before stopping from the time the driver applied the brake can be obtained as follow:

s = (u + v)t/2

s = (30 + 0)1.5 / 2

s = (30 × 1.5) / 2

s = 45 / 2

s = 22.5 m

Thus, the car will move to a distance of 22.5 m before stopping from the time the driver applied the brake.

4 0
3 years ago
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