ASAP MULTIPLE CHOICE

What mass of cu(s)cu(s) is electroplated by running 14. 5 aa of current through a cu2 (aq)cu2 (aq) solution for 4. 00 hh?

galina1969 [7]

The mass of Copper electroplated is 68.76 g

<h3>What is electroplating?</h3>

The process of plating a metal onto another is known as electroplating.

It is often used to prevent corrosion of metal or for the decorative purposes

In this process, electric current is passed through an aqueous solution containing dissolved cations.

The dissolved cations are reduced developing a thin metal coating on the electrode.

At cathode,

$Cu^{2+}(aq) + 2e^-\rightarrow Cu(s)$

Current, I = 14.5 A

Time, t = 4 hrs = 4×60×60 = 14400 sec

Charge, q = It = 14.5×14400= 208800 C

Copper metal deposited by 2×96487 C = 63.55 g

Copper metal deposited by 208800 C = $\frac{63.55 \times208800}{2\times96487}$

= 68.76g

Hence, The mass of Copper electroplated is 68.76 g

Learn more about electroplating:

brainly.com/question/22104403

#SPJ4

4 0

1 year ago

Read 2 more answers

In a chemical equation, the symbol that means "dissolved in water" is _____. (s) (l) (aq) (g)

Paraphin [41]

In a chemical equation, the symbol that means “dissolved in water” is (aq).

8 0

2 years ago

During a laboratory experiment, 9.68 g of iron reacted with excess sulfur to form 13.8 grams of iron II sulfide. Calculate the p

Daniel [21]

Answer:

Percent yield = 90.8%

Explanation:

The reaction of Fe with S to produce FeS is:

Fe + S → FeS

<em>Where the moles of Fe added in excess of S are the moles of FeS</em>

<em />

Now, percent yield is defined as 100 times the ratio between actual yield (13.8g of FeS) and theoretical yield (15.2g FeS):

Percent yield = 13.8g / 15.2g * 100

<h3>Percent yield = 90.8%</h3>

5 0

3 years ago

Please help bbg'sssss

shutvik [7]

Answer:

Explanation:

from the way the trees look, i would say A: Wind from the sky, it seems B: Clouds and in the distance C:Precipitation(rain)

7 0

3 years ago

A 4.00L flask containing Ne at 25 C and 6.00 atm is joined by a valve to an 8.00 L flask Ar at 25 C and 2.00 atm.

timama [110]

Answer:

$P=3.33atm$

Explanation:

Hello!

In this case, since know the volume, temperature and pressure of the initial containers, we can compute the moles of each gas prior to the opening of the valve as shown below:

$n_{Ne}=\frac{6atm*4L}{0.08206\frac{atm*L}{mol*K}*298.15K} =0.981molNe\\\\n_{Ar}=\frac{2atm*8L}{0.08206\frac{atm*L}{mol*K}*298.15K} =0.654molAr$

Next, we add them up to obtain the total moles:

$n_T=0.981mol+0.654mol=1.635mol$

Now, the total volume:

$V_T=4.00L+8.00L=12.00L$

Finally, the total pressure is computed by using the ideal gas equation:

$P=\frac{1.635mol*0.08206\frac{atm*L}{mol*K}*298.15K}{12.00L}\\\\P=3.33atm$

Best regards!

6 0

3 years ago