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snow_lady [41]
3 years ago
13

A category of classification below a kingdom? A phylum B domain C species

Chemistry
1 answer:
Nutka1998 [239]3 years ago
3 0

Answer:

Phylum

Explanation:

After that it goes class, order, family, genus, and finally species. In that order, BTW before kingdom is domain.

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Convert 2.859 liters to milliliters..
Elden [556K]

Answer:

2859 milliliters

Explanation:

Just move the decimal to the left and you get this as your answer

Formula : multiply the volume value by 1000

Hope this helps :)

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How many grams of H2 are needed to produce 13.33g of NH3?
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The reaction to form NH3 is : N2 + 3H2-> 2NH3 12,33g NH3 is 12,33/17,03=0,3 =0,724 moles of NH3 moles NH3. So you need 1,5*0,724 = 1,086 moles H2 1,086*2,016 = 2,189 g of H2 is needed ro form 12,33 g NH3

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4.The other light bulb will stay on and glow brightly.
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2 years ago
The reducing agent in this catalytic hydrogenation reaction was molecular hydrogen (H2), which was produced in situ (in the reac
creativ13 [48]

Answer:

a)  After the balloon inflated after 440 uL of dropwise due to the reaction of 1-Decene and the solution in the conical vial. b) 4NaBH_{4} + 2HCl + 7H_{2}O ⇒ 16H_{2(g)}+ 2NaCl + Na_{2}B_{4}O_{7} c) No H_{2} was not the limiting reactant.

Explanation:

Generally, hydrogenation is the chemical reaction between a compound or element and molecular hydrogen in the presence of catalysts such as platinum.

a) After the balloon inflated after 440 uL of dropwise 1-Decene solution was added due to the reaction between 1-Decene and the solution in the conical vial.

b)  4NaBH_{4} + 2HCl + 7H_{2}O ⇒ 16H_{2(g)}+ 2NaCl + Na_{2}B_{4}O_{7}

c) H_{2} was not the limiting reactant based on the mol to mol ratio of H_{2} and decane which is 1:1. Therefore, if 0.8 mol of decane was produced then 0.8 mol of H_{2} would also be produced.

4 0
3 years ago
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