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3 years ago

The density of mercury (hg, a liquid metal) is 13.6 g/ml. how much would 18.0 ml of mercury weigh?

Chemistry

1 answer:

Bogdan [553]3 years ago

7 0

Density of Mercury = 13.6 g/ml

Volume of mercury = 18.0 ml

Weight of Mercury = ?

By using the formula

Density = Mass / Volume or

D = M / V

M = D x V

Putting the values of D and V

M = 13.6g/ml x 18.0ml

M = 244.8 g

So the Mercury weighs 244.8 g

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Radio waves travel at the speed of light which is 3.00 x 10^8. How many minutes does it take for a radio message to reach saturn

ryzh [129]

Answer:

43.89 min

Explanation:

Given that:-

The speed of light = $3.00\times 10^8\ m/s$

The distance = $7.9\times 10^8\ km$

The conversion of distance in km to distance into m is shown below as:-

1 km = 1000 m

So,

Distance = $7.9\times 10^8\times 1000\ m=7.9\times 10^{11}\ m$

The relation between speed distance and time is shown below as:-

$Speed=\frac{Distance}{Time}$

Thus,

$3.00\times 10^8=\frac{7.9\times 10^{11}}{Time}$

$300000000\times time=10^{11}\times \:7.9\ s$

Time = 2633.33 seconds

Also, 1 s = 1/60 min

So,

Time= $\frac{2633.33}{60}\ min=43.89\ min$

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3 years ago

If two substances travel up the chromatography paper this implies that

Colt1911 [192]

Answer:

They are seperating

Explanation:

6 0

3 years ago

Consider the following intermediate chemical equations.

QveST [7]

Answer: 250 kJ

Explanation: According to Hess’s law of constant heat summation, the heat absorbed or evolved in a given chemical equation is the same whether the process occurs in one step or several steps.

According to Hess’s law, the chemical equation can be treated as algebraic expressions and can be added or subtracted to yield the required equation. That means the enthalpy change of the overall reaction is the sum of the enthalpy changes of the intermediate reactions.

$P_4(s)+6Cl_2\rightarrow 4PCl_3$ $\Delta H_1=-2439kJ$ (1)

$4PCl_5(g)\rightarrow P_4(s)+10Cl_2(g)$ $\Delta H_2=3438kJ$ (2)

Net chemical equation:

$PCl_5(g)\rightarrow PCl_3(g)+Cl_2(g)$ $\Delta H=?$ (3)

Adding 1 and 2 we get,

$4PCl_5(g)\rightarrow 4PCl_3(g)+4Cl_2$ $\Delta H_3=\Delta H_1+\Delta H_2=-2439+3438=1000kJ$ (4)

Now dividing equation (4) by 4, we get

$PCl_5(g)\rightarrow PCl_3(g)+Cl_2$

$\Delta H=\frac{\Delta H_3}{4}=\frac{1000kJ}{4}=250kJ$ (4)

8 0

3 years ago

What is the relationship between a mole and Avogadro number

docker41 [41]

A mole contains Avogadro’s number of particles of a substance.

4 0

3 years ago

Read 2 more answers

Hydrocarbons, compounds containing only carbon and hydrogen, are important in fuels.The heat of combustion of cyclopentane, C5H1

shtirl [24]

Answer : The balanced equation for the complete combustion of cyclopentane will be :

$2C_5H_{10}+15O_2\rightarrow 10CO_2+10H_2O$

Explanation :

As we know that the hydrocarbons can undergo complete or incomplete combustion that depends on the amount of oxygen available.

Complete combustion : It takes place when there is a good supply of oxygen. In this, hydrocarbon react with the oxygen to give carbon dioxide and water as a product.

The general reaction will be :

$\text{Hydrocarbon}+O_2\rightarrow CO_2+H_2O$

Incomplete combustion : It takes place when there is a poor supply of oxygen. In this, hydrocarbon react with the oxygen to give carbon monoxide, carbon dioxide and water as a product.

The general reaction will be :

$\text{Hydrocarbon}+O_2\text{(limited)}\rightarrow CO+CO_2+H_2O$

As per question, the complete combustion of cyclopentane react with oxygen to gives carbon dioxide and water as a product.

Therefore, the balanced chemical reaction will be :

$2C_5H_{10}+15O_2\rightarrow 10CO_2+10H_2O$

7 0

3 years ago