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djyliett [7]
3 years ago
14

PLEASE HELP ME DUE TOMORROW IT REALLY HELPS IF YOU HELP ME THANK YOU SO MUCH IS YOU DO HELP ME!!

Chemistry
1 answer:
aliya0001 [1]3 years ago
3 0

concentration of the contact solution = 3 %

Explanation:

We have the following data:

10.7 g of hydrogen peroxide H₂O₂

355 g of solution

To calculate the concentration of the contact solution we use the following formula:

concentration = (mass of solute / mass of solution) × 100

concentration of the contact solution = (10.7 / 355) × 100

concentration of the contact solution = 3 %

Learn more about:

concentration of solutions

brainly.com/question/7053858

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Which pair of reactants will undergo aldol condensation to produce methylvinyl ketone?
xenn [34]

When formaldehyde and acetone then react with each other( aldol condensation) then it will be formed <u> methyl vinyl ketone.</u>

<u />

In organic chemistry, an aldol condensation would be a condensation reaction in which an enol and enolate ion combines with a carbonyl chemical to produce a -hydroxy aldehyde or -hydroxy ketone, that is then dehydrated to produce a conjugated enone.

In aldol condensation, when  formaldehyde and acetone then react with each other then it will be formed <u> </u><u>methyl vinyl ketone.</u>

It can be written as

CH_{2} O + CH_{3} COCH_{3} → HOCH_{2} -CH_{2} -CO-CH_{3}

When it will be heated then it gives methyl vinyl ketones.

HOCH_{2} -CH_{2} -CO-CH_{3} → CH_{2} =CH-CO-CH_{3}

So, the pair of reactants will be formaldehyde and acetone

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6 0
2 years ago
Explain the chemistry behind global warming in 3-5 sentences
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Answer:

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8 0
3 years ago
Electron A falls from energy level X to energy level Y and releases blue light. Electron B falls from energy level Y to energy l
MrMuchimi

Answer: Transition from X to Y will have greater energy difference.

Explanation: For studying the energy difference, we require Planck's equation.

                                E=\frac{hc}{\lambda}

where, h = Planck's Constant

c = Speed of light

E = Energy

\lambda = Wavelength of particle

From the equation, it is visible that the energy and wavelength follow inverse relation which means that with low wavelength value, energy will be the highest and vice-versa.

As electron A falls from X-energy level to Y-energy level, it releases blue light which has low wavelength value (around 470 nm) which means that it has high energy.

Similarly, Electron B releases red light when it falls from Y-energy level to Z-energy level, which has high wavelength value (around 700 nm), giving it a low energy value.

Energy Difference between X-energy level and Y-energy level will be more.


5 0
3 years ago
Which bond has the greatest ionic character? A) H-Cl B) H-F c) H-O d) H-N
Len [333]
 I really hope that this helps.  H-F because the difference in electronegativity is the greatest, about 1.9 on the Pauling scale. The term means which bond has the greatest polarity and is thus most similar to an ionic bond, which involves the transfer of an electron (in opposition to covalent bonds, which share electrons). It is H-F because out of all the atoms here bonded with H, ie hydrogen, F is the most electronegative which means it can pull the bonded electrons to itself more than can Cl, O, and N. <span>That means a stronger polarization of the electron cloud forming the bond with hydrogen and therefore a stronger ionic character.</span>
5 0
3 years ago
A 1.0l buffer solution contains 0.100 mol of hc2h3o2 and 0.100 mol of nac2h3o2. the value of ka for hc2h3o2 is 1.8×10−5. part a
Mandarinka [93]
There are two ways to solve this problem. We can use the ICE method which is tedious and lengthy or use the Henderson–Hasselbalch equation. This equation relates pH and the concentration of the ions in the solution. It is expressed as

pH = pKa + log [A]/[HA] 

 where pKa = - log [Ka]
[A] is the concentration of the conjugate base
[HA] is the concentration of the acid

Given:
Ka = 1.8x10^-5
NaOH added = 0.015 mol
HC2H3O2 = 0.1 mol
NaC2H3O2 = 0.1 mol

Solution:
pKa = - log ( 1.8x10^-5) = 4.74

[A] = 0.015 mol + 0.100 mol = .115 moles
[HA] = .1 - 0.015 = 0.085 moles

pH = 4.74 + log (.115/0.085)
pH = 4.87
6 0
3 years ago
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