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3 years ago

What is the formula of arsenic hexabromide?

1 answer:

6 0

When dealing with compounds and their names, it helps to know the prefixes of some of the common compounds. For instance,

Mono- = 1
Di- = 2
Tri- = 3
Tetra- = 4
Penta- = 5
Hexa- = 6

And the list goes on.

However we are dealing with Arsenic Hexabromide:

That means we have 1 Arsenic with 6 Bromides:

$AsBr_{6}$

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Breaking larger molecules into smaller molecules and carbon

ella [17]

Answer: catabolism

Explanation:

Catabolism refers to the set of metabolic pathways which is necessary for the breaking down of molecules into smaller units. This is then oxidized for the release of energy or can be used to perform other anabolic reactions.

Catabolism is regarded as the opposite direction of anabolism which is simply the building-up of molecules. It should be noted that anabolism and catabolism work together in every living organisms and perform functions such as the production of energy and the repair of cells.

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3 years ago

The rate of disappearance of HBr in the gas phase reaction 2 HBr(g) → H2(g) + Br2(g) is 0.140 M s-1 at 150°C. The rate of appear

djverab [1.8K]

Answer: The rate of appearance of $Br_2$ is $0.0700Ms^{-1}$

Explanation:

Rate law says that rate of a reaction is directly proportional to the concentration of the reactants each raised to a stoichiometric coefficient determined experimentally called as order.

$2HBr(g)\rightarrow H_2(g)+Br(g)$

The rate in terms of reactants is given as negative as the concentration of reactants is decreasing with time whereas the rate in terms of products is given as positive as the concentration of products is increasing with time.

Rate in terms of disappearance of HBr = $-\frac{1d[HBr]}{2dt}Rate in terms of appearance of [tex]H_2$ = $\frac{1d[H_2]}{dt}$

Rate in terms of appearance of $Br_2$ = $\frac{1d[Br_2]}{dt}$

$-\frac{1d[HBr]}{2dt}=\frac{d[H_2]}{dt}=\frac{d[Br_2]}{dt}$

Given :

$-\frac{1d[HBr]}{dt}=0.140Ms^{-1}$

The rate of appearance of $Br_2$ ;

$\frac{1d[Br_2]}{dt}=-\frac{1d[HBr]}{2dt}=\frac{1}{2}\times 0.140=0.0700Ms^{-1}$

Thus rate of appearance of $Br_2$ is $0.0700Ms^{-1}$

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3 years ago

The energy levels of the positive ions that have just a single electron, like He , Li2 , or Be3 , etc., follow the formula Bohr

Sidana [21]

The answer is false. Hope that helps

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3 years ago

The specific heats and densities of several materials are given below: Material Specific Heat (cal/g·°C) Density (g/cm3) Brick 0

abruzzese [7]

<u>Answer:</u> The change in temperature is 84.7°C

<u>Explanation:</u>

To calculate the change in temperature, we use the equation:

$q=mc\Delta T$

where,

q = heat absorbed = 1 kCal = 1000 Cal (Conversion factor: 1 kCal = 1000 Cal)

m = mass of steel = 100 g

c = specific heat capacity of steel = 0.118 Cal/g.°C

$\Delta T$ = change in temperature = ?

Putting values in above equation, we get:

$1000cal=100g\times 0.118cal/g^oC\times \Delta T\\\\\Delta T=\frac{1000cal}{100g\times 0.118cal/g^oC}\\\\\Delta T=84.7^oC$

Hence, the change in temperature is 84.7°C

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3 years ago

Which of the following is a way your body fights a bacterial infection? Fever Shivers Sweats Increased heart rate

faust18 [17]

Bacterial infection disrupt the normal function of the body by causing illnesses.The immune system is compromised. The body uses its white blood cells to fight bacterial infection. Some of the ways your body fights these bacterial infections is a fever.

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