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Elza [17]
3 years ago
10

What is the formula of arsenic hexabromide?

Chemistry
1 answer:
Nady [450]3 years ago
6 0
When dealing with compounds and their names, it helps to know the prefixes of some of the common compounds. For instance,

Mono- = 1
Di- = 2
Tri- = 3
Tetra- = 4
Penta- = 5
Hexa- = 6

And the list goes on.

However we are dealing with Arsenic Hexabromide:

That means we have 1 Arsenic with 6 Bromides:

AsBr_{6}
You might be interested in
Write the beta decay equation for the following isotope: 91 38 Sr? Please write out steps
babymother [125]

Answer:

\rm _{38}^{91}Sr \longrightarrow \,  _{-1}^{0}e + \,  _{39}^{91}Y

Explanation:

The unbalanced nuclear equation is

\rm _{38}^{91}Sr \longrightarrow \,  _{-1}^{0}e \, + \, ?

Let's write the question mark as a nuclear symbol.

\rm _{38}^{91}Se} \longrightarrow \,  _{-1}^{0}e \, + \,  _{Z}^{A}X

The main point to remember in balancing nuclear equations is that the sums of the superscripts and the subscripts must be the same on each side of the equation.  

Then

98 =  0 + A, so A =  98 -  0 = 98, and

38 = -1 + Z, so Z  = 38 + 1 = 39

Then, your nuclear equation becomes

\rm _{38}^{91}Sr \longrightarrow \,  _{-1}^{0}e + \,  _{39}^{91}X

Element 39 is yttrium, so the balanced nuclear equation is

\rm _{38}^{91}Sr \longrightarrow \,  _{-1}^{0}e + \,  _{39}^{91}Y

7 0
3 years ago
What is paper chromatography? Calculate the Rr value of a colored dye that traveled 52 mm on a chromatography strip while the so
Karo-lina-s [1.5K]

Answer:

Paper chromatography is a basic technique of chromatography. It consist in the separation of the mixe components using a solvent.

Explanation:

Paper chromatography is a basic technique of chromatography. It consists in the separation of the mixed components using a solvent.

Paper chromatography consists of put some dot of the mix using a glass capillary into a specialized paper, generally made of cellulose, this is called a stationary phase.

Then you put this paper into a camera of glass named, chromatography camera, where previously contain a solvent. The solvent also know as a mobile phase, the type can be defined before the test and involves a study of the kind of the mix, and the compound you want to separate.

The chromatography camera has to be closed all the time during the test, and you can't move at all because the movement of the solvent can alternate the result.

Very often, the solution of the solvent is a mix of different liquid substances with different polarities.

When the stationary phase put into the camera, the solvent starts to move up over the paper, until the separation of the compounds is observable.

the Rf is a value who relates the move of the mobile phase with the move of the distance traveled by the substance tested.

To undersant the paper chromatography, you can watch the images attached.

The first is an image of the chromatography camera.

The second one is an image of a cellulose paper after the chromatography is done. You can watch the dots who indicates the traveling of the compound across the paper.

The third one can show you the evolutions of paper chromatography, from the beginning to the end.

To calculate the Rf value you have to use the equation:

Rf = distance traveled by the substance/distance traveled by the solvent/

<u>Rf = 52mm/81mm =0.64</u>

<u></u>

3 0
3 years ago
What is the volume (in liters) of a 5.52 gram sample of O2 at STP?
OverLord2011 [107]

Answer:

1

Recall that at STP, 1 mole of any ideal gas occupies 22.4 liters. Volume O2 gas = 0.0510 moles O2 x 22.4 L/mole = 1.14 liters (3 sig.

Explanation:

hope this helps

4 0
2 years ago
How does concentration affect our daily lives in science?​
statuscvo [17]

1. <em>Increasing the concentration of one or more reactants will often increase the rate of reaction. This occurs because a higher concentration of a reactant will lead to more collisions of that reactant in a specific time period. </em>

<em>2. Physical state of the reactants and surface area.</em>

8 0
3 years ago
Which has the most gravitational potential energy- a 10 kg ball that is 2 meters high or a 10 kg ball that is 4 meters high?
Alenkasestr [34]

Answer:

The 10 kg ball that is 4 meters high is greater than a 10 kg ball that is 2 meters high

Explanation:

From the question,

Gravitational Potential Energy of the first ball

P.E1 = mgh.................... Equation 1

Where P.E1 = Gravitational Potential Energy of the first ball, m = mass of the first ball, h = height of the first ball, g = acceleration due to gravity.

Given: m = 10 kg, h = 2 m

Constant: g = 9.8 m/s²

Substitute these values into equation 1

P.E1 = 10×2×9.8

P.E1 = 196 J.

Similarly,

Gravitational potential energy of the second ball is

P.E2 = m'gh'................... Equation 2

Where P.E2 = Gravitational potential Energy of the second ball, m' = mass of the second ball, h' = height of the second ball.

Given; m' = 10 kg, h' = 4 m

Substitute these values into equation 2

P.E2 = 10×4×9.8

P.E2 = 392 J

From the above calculation,

P.E2 is greater than P.E1.

Hence, the 10 kg ball that is 4 meters high is greater than a 10 kg ball that is 2 meters high

3 0
3 years ago
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