All categories

2 years ago

Which of the following shows the path followed by nerve impulses in a reflex?

Chemistry

2 answers:

Anastasy [175]2 years ago

5 0

D. sensory neurons-> interneurons in spinal cord-> motor neurons. I did my research

lana [24]2 years ago

4 0

<h2>Nerve Impluses In a Reflex - Option C </h2>

Sensory neurons, interneurons in spinal cord, motor neurons shows the path followed by nerve impulses in a reflex. Sensory neurons are the neurons that carry information from the environment externally to the central nervous system (CNS) mainly brain and motor neurons are those which carry information from CNS to other parts.

A human perceives something then by sensory neurons the information goes to CNS and that information is further passed by interneurons in spinal cord and is further passed by motor neurons from CNS to other parts to perform stimulus of perception.

You might be interested in

Which of the following statements is true?

dybincka [34]

Answer:C

Explanation:

A process is called spontaneous if the process takes place on its own without the intervention of external factors.

The spontaneous processes are generally quick with observable rates of reaction.But processes can be spontaneous even with negligible rates of reaction.

Spontaneity of reactions depend on temperature.

This is because spontaneity is measured by gibbs energy or enthalpy.

Both of these measures are dependent on temperature.

So,temperature affects spontaneity.

7 0

2 years ago

HELP!!! The periodic change between night and day is caused by ____________.

charle [14.2K]

Answer:

C. Earth's revolution around the sun

Explanation:

4 0

2 years ago

Sholpan [36]

Answer: Your mass would be the same, but you would weigh less because the gravity on the moon is less than it is on Earth.

Explanation:

7 0

3 years ago

In this experiment, 0.070 g of caffeine is dissolved in 4.0 ml of water. The caffeine is then extracted from the aqueous solutio

Damm [24]

2.0ml of methylene chloride solution is used each time to extract caffeine from the aqueous solution.

Consider the concentration of caffeine obtained during each individual extraction from the aqueous solution to be C.

The total amount of caffeine obtained during each extraction is calculated as

(Total volume of water used to make up the caffeine aqueous solution) x (concentration of caffeine obtained during each individual extraction from the aqueous solution) + (Volume of methylene chloride added during each extraction x distribution coefficient of caffeine x concentration of caffeine obtained during each individual extraction from the aqueous solution)

Substituting these values we get

The total amount of caffeine obtained during each extraction

= (4.0×C )+ (2.0×4.6 × C)

= 13.2 C

The amount of caffeine remaining in the aqueous solution is calculated as

(Total volume of water used to make up the caffeine aqueous solution) x (concentration of caffeine obtained during each individual extraction from the aqueous solution)

Substituting these values we get

The amount of caffeine remaining in the aqueous solution = 4 × C

The fraction of caffeine remaining in aqueous solution is calculated as

= (The total amount of caffeine obtained during each extraction)/ (The amount of caffeine remaining in the aqueous solution)

=4.0 C/13.2 C

= 1/3.3.

Therefore the fraction of caffeine left in aqueous solution after 3 extractions is =(1/3.3)^3 =0.028

Therefore, the total amount of caffeine extracted

=0.070 × (1-(1/3.3)^3)

= 0.068 g

5 0

3 years ago

Read 2 more answers

What is the average yearly rate of change of carbon-14 during the first 5000 years?

erica [24]

Answer:

The average yearly rate of change of carbon-14 during the first 5000 years = 0.0004538 grams per year

Explanation:

Given that the mass of the carbon 14 at the start = 5 gram

At the end of 5,000 years we will have;

$A = A_0 \times e^{-\lambda \times t}$

Where

A = The amount of carbon 14 left

A₀ = The starting amount of carbon 14

e = Constant = 2.71828

$T_{1/2}$ = The half life

$\lambda = 0.693/T_{1/2}$

t = The time elapsed = 5000 years

λ = 0.693/ $T_{1/2}$ = 0.693/5730 = 0.0001209424

Therefore;

A = 5 × e^(-0.0001209424×5000) = 2.7312 grams

Therefore, the amount of carbon 14 decayed in the 5000 years is the difference in mass between the starting amount and the amount left

The amount of carbon 14 decayed = 5 - 2.7312 = 2.2688 grams

The average yearly rate of change of carbon-14 during the first 5000 years is therefore;

2.2688 grams/(5000 years) = 0.0004538 grams per year

The average yearly rate of change of carbon-14 during the first 5000 years = 0.0004538 grams per year.

5 0

3 years ago