Answer:
Si tú puedes 1-2-3-4-5-6-7-8-9-10 eso debes de ser más bien dicho sacaran Club Ojalá que te ayude Chau
Explanation:
de Ojalá que te ayude No te olvides de sacar todas las preguntas esas lo que tú dijiste y si tú promoción 123 saquen globo que quieras tú
Answer is: adding NaCl will lower the freezing point of a solution.
A solution (in this example solution of sodium chloride) freezes at a lower temperature than does the pure solvent (deionized water).
The higher the solute concentration (sodium chloride), freezing point depression of the solution will be greater.
Equation describing the change in freezing point:
ΔT = Kf · b · i.
ΔT - temperature change from pure solvent to solution.
Kf - the molal freezing point depression constant.
b - molality (moles of solute per kilogram of solvent).
i - Van’t Hoff Factor.
Dissociation of sodium chloride in water: NaCl(aq) → Na⁺(aq) + Cl⁻(aq).
Plants that have nigrogen fixing bacteria in their roots are called
legumes.
I think the correct answer from the choices listed above is option C. Chemical reaction is the process <span>that changes one set of chemicals into another set of chemicals. In a chemical reaction, old bonds are broken down forming new bonds therefore new </span>substances<span> with new properties.</span>
Answer:
Adding 1 mol of NaCl to 1 kg of water lower the vapor pressure of water <em><u>to the same extent</u></em> by adding 1 mol of 
to 1 kg of water.
Explanation:
1) Moles of NaCl ,
Mass of water = m= 1 kg = 1000 g
Moles of water = 
Vapor pressure of the solution = 
Vapor pressure of the pure solvent that is water = 
Mole fraction of solute(NaCl)= 
The vapor pressure for the NaCl solution at 17.19 Torr.
2) Moles of sucrose ,
Mass of water = m = 1 kg = 1000 g
Moles of water =
Vapor pressure of the solution = 
Vapor pressure of the pure solvent that is water =
Mole fraction of solute ( glucose)=
The vapor pressure for the glucose solution at 17.19 Torr.
p = p' = 17.19 Torr
Adding 1 mol of NaCl to 1 kg of water lower the vapor pressure of water to the same extent by adding 1 mol of to 1 kg of water.
