Answer:
74.09 atm
Explanation:
Using the gas laws ( Charles and Boyle's law). We have the formula ,
P1/T1 = P2/T2
Where P1 = 30.3atm
T1 = -100 degree Celsius
to kelvin = -100+ 273 = 173K
T2 = 150 degree Celsius
To Kelvin = 150 = 150+273 = 423K
Imputing values
P1/T1 = P2/T2
30.3/173 = P2/ 423
Cross multiply
173×P2 = 30.3 ×423
173P2 = 12816.9
Divide both sides by 173
P2 = 12816.9/173
P2 = 74.09 atm
I hope this was helpful, please mark as brainliest
oxygen and silicon I believe
Answer:
xy (-b+c+q) is the answer to this
Answer:
CH3CH2NH3+/CH3CH2NH2 would have the largest pKa
Explanation:
To answer this question we must know Kb of CH3CH2NH2 is 5.6x10⁻⁴, and for C6H5NH2 is 4.0x10⁻¹⁰. And the CH3CH2NH3+ and C6H5NH3+ are related with these substances because are their conjugate base. That means:
pKa of CH3CH2NH3+ = CH3CH2NH2; C6H5NH3+ = C6H5NH2
Also, Kw / Kb = Ka
Thus:
pKa of CH3CH2NH3+/CH3CH2NH2 is:
Kw / kb = Ka = 1.79x10⁻¹¹
-log Ka = pKa
pKa = 10.75
pKa of C6H5NH3+/ C6H5NH2 is:
Kw / kb = Ka = 2.5x10⁻⁵
-log Ka = pKa
pKa = 4.6
That means CH3CH2NH3+/CH3CH2NH2 would have the largest pKa
