Ice, water, fog/water vapor
Answer:
the answer is 70.906 g/mol
Explanation:
Answer:
The answer to your question is m = 1.6
Explanation:
Data
mass of NaCl = 111 g
volume of water = 1.2 L
Molality = ?
Formula
Molality = number of moles / volume (L)
Process
1.- Calculate the moles of NaCl
Molecular mass = 23 + 35.5 = 58.5 g
1 mol of ------------------- 58.5 g
x -------------------- 111 g
x = (111 x 1) / 58.5
x = 1.897 moles of NaCl
2.- Calculate the mass of water
density of water = 997 kg/m³
mass = volume x density
mass = 0.0012 x 997
mass = 1.19 kg
3.- Calculate molality
m = 1.897/1.19
m = 1.6
Answer:
The ΔH°rxn for this reaction is -905.9 kJ
Explanation:
<u>Step 1:</u> Balanced reaction:
4NH3(g) + 5O2(g) --> 4NO(g) + 6H2O(g)
<u />
<u>Step 2</u>: Given data
ΔH°f [NH3(g)] = –45.9 kJ/mol
ΔH°f [NO(g)] = 90.3 kJ/mol
ΔH°f [H2O(g)] = –241.8 kJ/mol
ΔH°f of O2 is defined to be zero
<u>Step 3</u>: Calculate ΔH°rxn
ΔH°rxn = ΔH°products - ΔH°reactants
ΔH°rxn = ((4*90.3) + 6*-(241.8)) - 4*(-45.9) = -905.9 kJ
The ΔH°rxn for this reaction is -905.9 kJ
