Answer:
Let the integers are p and q.
In case both integers are positive or negative, you add the numbers up and apply their sign to the sum.
<u>Examples:</u>
- 10 + 88 = 98
- -20 + (-15) = -35
In case one of the integers is negative and one positive.
Use absolute value in this case.
Subtract the numbers and apply the sign of the number with the greater absolute value.
<u>Examples:</u>
- - 10 + 15 = |15 - 10| = |5| = 5
- - 15 + 10 = - |15 - 10| = - |5| = -5
Answer:
x³ - 3x² - 9x + 27
= x²(x - 3) - 9(x - 3)
= (x² - 9)(x - 3)
= (x -3)(x + 3)(x - 3)
= (x + 3)(x - 3)²
Step-by-step explanation:
The answer is y= a/3(3+x)
d/dx cos^2(5x^3)
= d/dx [cos(5x^3)]^2
= 2[cos(5x^3)]
= - 2[cos(5x^3)] * sin(5x^3)
= - 2[cos(5x^3)] * sin(5x^3) * 15x^2
= - 30[cos(5x^3)] * sin(5x^3) * x^2
Explanation:
d/dx x^n = nx^(n - 1)
d/dx cos x = - sin x
Chain rule:
d/dx f(g(...w(x))) = f’(g(...w(x))) * g’(...w(x)) * ... * w’(x)
