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horrorfan [7]
3 years ago
7

The velocity of a wave is primarily determined by the

Physics
1 answer:
tamaranim1 [39]3 years ago
8 0
<h2>Answer: medium  </h2><h2 />

The propagation velocity of a wave depends on the medium in which it propagates.  

In addition, it depends on the type of wave, for example a mechanical or electromagnetic wave.  

In any case, the velocity of a wave is generally related to the value of the wavelength and the period, and can be expressed mathematically through the following formula:  

v=\frac{\lambda}{T}

where v is the velocity of the wave, \lambda is the wavelength and T is the period.

Therefore:

<h2>The propagation velocity of a wave depends on the <u>medium</u></h2>

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A. How will the Milky Way continue to move outward as a result of the Big Bang?
emmasim [6.3K]

Answer:

i believe it is c

Explanation:

4 0
3 years ago
The y-component of the force F which a person exerts on the handle of the box wrench is known to be 86 lb. Determine the x-compo
emmainna [20.7K]

Answer:

x-component of force is  38.18 lb where as magnitude of Force is 93.16

Explanation:

Fy of the force F exerted on the handle of the box wrench = 86 lb

Considering the triangle in Fig 1

magnitude of perpendicular = P =  12

magnitude of base = B = 5

using Pythagoras theorem

                        H= \sqrt{P^{2} + B^{2}}

                 H= \sqrt{12^{2} + 5^{2}}

            H=13\\\implies cos \theta = \frac{5}{13} \\\implies sin \theta = \frac{12}{13}\\

y-component of force is given given as:

                              86 = Fsin\theta\\F = 86 (\frac{13}{12})\\F = 93.16 lb\\F_{x} =F cos \theta\\F_{x} = 93.16 (\frac{5}{13})\\F_{x} =38.18 lb.

5 0
3 years ago
HELLPPPP. The metalloid that has three valence electrons is ___________?​
Alja [10]

Answer:

Boron

Explanation:

8 0
2 years ago
The distance-time graph for a faster moving object has a smaller slope than the graph for a slower moving object. True or false
allsm [11]
False because faster moving slope would be going up and slower would be going down because its decreasing 
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2 years ago
Read 2 more answers
An ice sled powered by a rocket engine starts from rest on a large frozen lake and accelerates at 12.8 m/s2 . At t1 the rocket e
Simora [160]

Answer:4.39 s

Explanation:

Given

initial velocity u=0

acceleration a=12.8 m/s^2

velocity acquired by sled in t_1 time

v=0+at

v=12.8t_1

distance traveled by sled in t_1 s

v^2-u^2=2as

(12.8t_1)^2-0=2\times 12.8\times s_1

s_1=6.4\cdot t_1^2

distance traveled in t_2 time with velocity v=12.8t_1

s_2=v\times t_2

s_2=12.8\times t_1\times t_2

s_2=12.8\cdot t_1\cdot t_2

s_1+s_2=5.37\times 10^3

6.4t_1^2+12.8t_1t_2=5370----1

t_1+t_2=97.7 s

t_2=97.7-t_1

substitute the value of t_2 in 1

we get

6.4t_1^2-1250.56t_1+5370=0

thus t_1=\frac{1250.56-1194.33}{12.8}=4.39 s

t_1=4.39 s

5 0
3 years ago
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