We are to show that the given parametric curve is a circle.
The trajectory of a circle with a radius r will satisfy the following relationship:
(with (x_c,y_c) being the center point)
We are given the x and y in a parametric form which can be further rewritten (using properties of sin/cos):
Squaring and adding both gives:
The last expression shows that the given parametric curve is a circle with the center (0,0) and radius A.
Answer:
<h2>10,000 J</h2>
Explanation:
The kinetic energy of an object can be found by using the formula
m is the mass
v is the velocity
From the question we have
We have the final answer as
<h3>10,000 J</h3>
Hope this helps you
Answer:
Groundwater occasionally discharges into surface water and then, they flow together as a body of water in a watershed.
Explanation:
According to www.mbgnet.net A watershed describes an area of land that contains a common set of streams and rivers that all drain into a single larger body of water, such as a larger river, a lake or an ocean.
Therefore, when groundwater discharges into a body of surface water, for example a stream, the stream just like several other streams in a watershed would flow into a larger body of water.
Answer: A- It would increase
Explanation:
According to the law of universal gravitation:
Where:
is the module of the attraction force exerted between both objects
is the universal gravitation constant.
and 
are the masses of both objects
is the distance between both objects
As we can see, the gravity force is directly proportional to the mass of the bodies or objects and inversely proportional to the square of the distance that separates them.
In other words:
<h2>If we decrease the distance between both objects, the gravitational force between them will increase. </h2>
Answer:
c = 1163.34 J/kg.°C
Explanation:
Specific heat capacity:
"Specific heat capacity is the amount of heat energy required to raise the temperature of a substance per unit of mass. The specific heat capacity of a material is a physical property."
Use this equation:
mcΔT = ( mw c + mAl cAl ) ΔT'
Rearranging the equation to find the specific heat (c) you get this:
c = (( mw c + mAl cAl ) ΔT') / (mΔT)
c = (( 0.285 (4186) + (0.15)(900)) (32 -25.1)) / ((0.125) (95 - 32))
c = 1163.34 J/kg.°C
