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3 years ago

if 4.12 L of 0.85-M H3PO4 solution is be diluted to a volume of 10.00 L,what is the concentration resulting solution

Chemistry

1 answer:

Alja [10]3 years ago

5 0

Answer:

The concentration resulting solution = 0.350 M

Explanation:

In case of dilution , the following formula can be used -

M₁V₁ = M₂V₂

where ,

M₁ = initial concentration ,

V₁ = initial volume ,

M₂ = final concentration , i.e. , concentration after dilution ,

V₂ = final volume .

from , the question ,

M₁ = 0.85 M

V₁ = 4.12 L

M₂ = ?

V₂ = 10.0 L

Using the above formula , the molarity of the final solution after dilution , can be calculated as ,

M₁V₁ = M₂V₂

0.85 M * 4.12 L = M₂ * 10.0 L

M₂ = 0.85 M * 4.12 L / 10.0 L

M₂ = 0.350 M

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1 year ago

Which scientist performed the cathode ray experiment leading to the discovery of electrons?

Drupady [299]

My answer -

The scientist that performed the cathode ray experiment leading to the discovery of electrons is the scientist Sir Joseph John Thompson or J.J. Thompson. It was theorized after the discovery that electrons are present in the atom. In this model, the atom is composed mainly of electrons. It was describe as plum pudding because the electrons are dispersed within the atom.

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3 years ago

Ferris & Mona used the ORP sensor to titrate a ferrous ammonium sulfate solution, (NH4)2Fe(SO4)2 with KMnO4 titrant.

DIA [1.3K]

Answer:

The correct option is: A. 0.168 M

Explanation:

Chemical reaction involved:

5 Fe²⁺ (aq) + MnO₄⁻ (aq) + 8 H⁺ (aq) → 5 Fe³⁺ (aq) + Mn²⁺ (aq) + 4 H₂O

Given: For MnO₄⁻ solution-

Number of moles: n₁ = 1, Volume: V₁ = 20.2 mL, Concentration: M₁ = 0.0250 M;

For Fe²⁺ solution:

Number of moles: n₂ = 5, Volume: V₂ = 15 mL, Concentration: M₂ = ?M

To find out the concentration of Fe²⁺ solution (M₂), we use the equation:

$\frac{M_{1}\times V_{1}}{n_{1}} = \frac{M_{2}\times V_{2}}{n_{2}}$

$\frac{0.0250 M\times 20.2 mL}{1} = \frac{M_{2}\times 15 mL}{5}$

$0.505 = M_{2}\times 3$

$M_{2} = \frac{0.505}{3} = 0.168M$

Therefore, the concentration or molarity of Fe²⁺ solution: M₂ = 0.168 M

8 0

3 years ago

How much volume would a 834.01g pile of sugar have given that it has a density of 1.59g/mL?

boyakko [2]

Answer:

v = 534.5mL

m = 597.15g

Density = 9.23g/mL

Density = 9.125g/mL

Explanation:

Density = mass/ volume

For the first question

Density = 1.59g/mL

Mass = 834.01g

Volume = ?

Using the above formula we have 1.59 = 834.01/v

v = 834.01/1.59

v = 534.5mL

For the second question

Density =0.9167g/mL

Volume = 651.41mL

Mass =?

Using the above formula we have

0.9167 =m/651.41

Cross multiply

m = 0.9167 x 651.41

m = 597.15g

For the third question

Mass =803.44g

Volume=87.03mL

Density =?

Density = 803.44/87.03

= 9.23g/mL

For the fourth

Density = 56.85/6.23

= 9.125g/mL

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3 years ago

Reduction is a reaction which results in a __1____ in electrons and a __2____ in positive charge of the atom or ion

mestny [16]

Hello! Your answer would be a gain of electrons and a decrease in positive charge.

Contrary to how it sounds, reduction is actually a gain of electrons. It is part of a set of reactions known as a redox reaction, reduction being a gain of electrons and oxidation being a loss.

With the gain of electrons, the element would become more negative as electrons bring with them a negative charge. Therefore, this would decrease the positive charge.

Hope this helped!

7 0

3 years ago