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3 years ago

Help meeee.... I'll give brainliest

Mathematics

1 answer:

serious [3.7K]3 years ago

8 0

Answer:

The independent variable is x and the dependent variable is y.

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What is 6/10 divided by 2/5

babunello [35]

Answer:3/2

Step-by-step explanation:

6/10 ➗ 2/5

6/10 x 5/2

(6x5)/(10x2)

30/20=3/2

3 0

3 years ago

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A number is not an interger.What type of number can it be?

EleoNora [17]

If it is not an integer, it would have to be a decimal.

4 0

3 years ago

Question 8

Lelechka [254]

Answer:

$695.88

Step-by-step explanation:

579 + 32 = 611

8% of 611 = 48.88

611 + 48.88 = 659.88

Stay safe! <3

6 0

3 years ago

Whats the lcm of 8 and 10

Firdavs [7]

The answer is 40. Hope this helped! Between 8 and 10, you can determine the least common multiple by multiplying. 8*5=40, and 10*4=40.

6 0

3 years ago

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Choose one of the factors of 500x3 + 108y18

sammy [17]

Answer:

Option C

Therefore, one of the factors of $500x^3 +108y^\left (18\right )$ is $(5x+3y^6)$ .

Step-by-step explanation:

Given: $500x^3 +108y^\left (18\right )$

the common factor from $500x^3$ and $108y^\left (18\right )$ is 4.

therefore, $4\cdot \left ( 125x^3+27y^\left (18\right ) \right )$

$4\cdot \left ( (5x)^3+(3y^6)^3 \right))$

Now, use the formula for above expression: $(a^3+b^3)=(a+b)(a^2-ab+b^2)$

here, $a=5x$ and $b=3y^6$

$( (5x)^3+(3y^6)^3 \right))$ $=(5x+3y^6)(25x^2-15xy^6+9y^12)$

Therefore, we have

$500x^3 +108y^\left (18\right )$ $=4\cdot (5x+3y^6)\left (25x^2-15xy^6+9y^\left ( 12 \right ) \right )$

Therefore, one of the factors of $500x^3 +108y^\left (18\right )$ is $(5x+3y^6)$ .

7 0

3 years ago

Read 2 more answers

Help meeee.... I'll give brainliest​

Help meeee.... I'll give brainliest