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Rufina [12.5K]
3 years ago
9

What does the second law of thermodynamics state?

Physics
1 answer:
bulgar [2K]3 years ago
3 0
In all energy transfers, if no energy leaves or enters the system, then the potential energy will always be less.
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Which of these galaxies would you most likely find at the center of a large cluster of galaxies?
Arada [10]

Answer:

b. a large elliptical galaxy

Explanation:

In elliptical galaxies the stars are grouped in an elliptical shape, it has a low quantity of gas and dust in comparison to spiral galaxies, and its stars belong to an old population, there is not new stellar formation in it.

The stars orbit in a messy way which made to believe that they form from the merger of galaxies.

They are also really massive (around 10^{4} solar masses).

The most massive and luminous can be found in the center of cluster of galaxies.  

4 0
3 years ago
What is the scientific revolution??
Basile [38]
The scientific revolution is a concept which explains how the developments of science (biology, chemistry, physics and etc.) changed the way we (society) think about nature. I hope this helps! :)
4 0
3 years ago
Can someone help me?
vlabodo [156]
1. Science.
2. evidence
6 0
3 years ago
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What is the wavelength of a wave that has a speed of 350 meters/second and a frequency of 140 hertz?In meters
Leto [7]
Apply:
wavelength = speed/frequency
= 350 m/s : 140 Hz = 2.5 m.
3 0
3 years ago
Read 2 more answers
A long jumper can jump a distance of 7.4 m when he takes off at an angle of 45° with respect to the horizontal. Assuming he can
GenaCL600 [577]

Answer:

0.02 m

Explanation:

R₁ = initial distance jumped by jumper = 7.4 m

R₂ = final distance jumped by jumper = ?

θ₁ = initial angle of jump = 45°

θ₂ = final angle of jump = 42.9°

v = speed at which jumper jumps at all time

initial distance jumped is given as

R_{1}=\frac{v^{2}Sin2\theta _{1} }{g}

final distance jumped is given as

R_{2}=\frac{v^{2}Sin2\theta _{2} }{g}

Dividing final distance by initial distance

\frac{R_{2}}{R_{1}}=\frac{Sin2\theta _{1}}{Sin2\theta _{2}}

\frac{R_{2}}{7.4}=\frac{Sin2(42.9)}{Sin2(45))}

R_{2} =7.38

distance lost is given as

d = R_{1} - R_{2}

d = 7.4 - 7.38

d = 0.02 m

8 0
3 years ago
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