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LekaFEV [45]
2 years ago
7

An 2.2 kg object accelerates at 4.0 m/s^2. What is the acceleration?

Physics
1 answer:
yanalaym [24]2 years ago
6 0

Answer:  12 N = ( 2 kg ) ( 6 m/s/s )

Explanation:

An accelertion of 6 m/s/s . If an object is in equilibrium, at rest, then, the net force on the object must be zero. That is, the sum of all the forces on an object is zero when the object is in equilibrium.

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A rabbit is hopping along at an approximately constant speed of 3.9 m/s. The rabbit passes a crouched cat ready to chase the rab
Firlakuza [10]

Answer:

t  = 7,8 s

Explanation:

From the instant, the rabbit passes the cat. The cat star running acceleration of 0,5 m/s² .

When the cat arrives at the speed of 3,9 m/s the cat catches the rabbit

Then for the cat arrives at 3,9 m/s nedds

v = vo + a*t     vo  = 0  then   v = a*t

3,9 ( m/s) = 0,5 ( m/s² ) * t

t  = 7,8 s

v  =  3,9 m/s =

4 0
3 years ago
A bead slides without friction around a loopthe-loop. The bead is released from a height 21.9 m from the bottom of the loop-the-
wariber [46]

Answer:

Part a)

v = 12.45 m/s

Part B)

F_n = 0.05 N

Explanation:

Part A)

As we know that the point A lies on the top of the loop

so we will have by energy conservation

mgH = \frac{1}{2}mv^2 + mg(2R)

so the speed at point A is given as

mg(H - 2R) = \frac{1}{2}mv^2

v = \sqrt{2g(H - 2R)}

v = \sqrt{2(9.81)(21.9 - 2\times 7)}

v = 12.45 m/s

Part B)

Now the force equation at point A is given as

F_n + mg = \frac{mv^2}{R}

F_n = \frac{mv^2}{R} - mg[/tex]

F_n = 0.004(\frac{12.45^2}{7} - 9.81)

F_n = 0.05 N

6 0
4 years ago
Which. describe newtons law of univesel gravitation
Fed [463]

Newton's law of universal gravitation, says that every particle attracts every other particle in the universe with a force which is directly proportional to the product of their masses and inversely proportional to the square of the distance between their centers.

Or in simple words, every particle in the world attracts each other to themselves, but the particle with most mass would attract with more force compared to a particle with less mass.

(<u><em>Please consider leaving a rate, a thanks and, a crown would be really appreciated! Thank you!</em></u>)

4 0
3 years ago
What percent of $ 40 is $ 32?<br><br>​
kumpel [21]

Answer:

80%

Explanation:

convert fraction ( ratio ) 32/40 answer 80%

4 0
4 years ago
Read 2 more answers
Practice: The speed of sound at sea level is normally about 340 m/s. A car honks its horn as it drives toward an observer. The f
stepan [7]

Answer:

25.5 m/s

Explanation:

The Doppler effect occurs when there is relative motion between a source of a wave and an observer. In such situation, there is a shift in the apparent frequency of the wave perceived by the observer.

The formula that gives the apparent frequency perceived by the observer is:

f'=\frac{v\pm v_o}{v\pm v_s}f

where

f is the real frequency of the wave

f' is the apparent frequency of the wave

v is the speed of the wave

v_s is the velocity of the source (negative if the source is moving towards the observer, positive otherwise)

v_o is the velocity of the observer (positive if the observer is moving towards the source, negative otherwise)

In this problem:

v = 340 m/s is the speed of sound

f = 800 Hz is the frequency of the horn

f' = 860 Hz is the apparent frequency

v_o=0 (the observer is at rest)

Re-arranging the equation for v_s, we can find the velocity of the horn and the driver:

f'=\frac{v}{v-v_s}f\\(v-v_s)f'=vf\\vf'-v_sf'=vf\\v_s=v\frac{f'-f}{f'}=(340)\frac{860-800}{860}=25.5 m/s

So, 25.5 m/s towards the observer.

3 0
3 years ago
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