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Gelneren [198K]
3 years ago
10

Calculate the boiling point of a 1.5 m aqueous solution of NaCl. The boiling point constant of water is 0.512 °C/m. Remember, m

is a unit for molality.
a.98.5 °C
b.100.0 °C
c.100.8 °C
d.101.5 °C
Chemistry
1 answer:
grigory [225]3 years ago
3 0

I think thee answer is C


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Answer:

The minimum molecular weight of the enzyme is 29.82 g/mol

Explanation:

<u>Step 1:</u> Given data

The volume of the solution = 10 ml = 10*10^-3L

Molarity of the solution = 1.3 mg/ml

moles of AgNO3 added = 0.436 µmol = 0.436 * 10^-3 mmol

<u>Step 2:</u> Calculate the mass

Density = mass/ volume

1.3mg/mL = mass/ 10.0 mL

mass = 1.3mg/mL *10.0 mL = 13mg

<u>Step 3:</u> Calculate minimum molecular weight

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34. 3.15 mol of an unknown solid is placed into enough water to make 150.0 mL of solution. The solution's temperature increases
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Answer:

ΔH = 2.68kJ/mol

Explanation:

The ΔH of dissolution of a reaction is defined as the heat produced per mole of reaction. We have 3.15 moles of the solid, to find the heat produced we need to use the equation:

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<em>Where q is heat of reaction in J,</em>

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The mass of the solution is obtained from the volume and the density as follows:

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Replacing:

q = 180.0g*4.184J/g°C*11.21°C

q = 8442J

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The ΔH of the reaction is:

8.44kJ/3.15 mol

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