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Natasha_Volkova [10]
3 years ago
14

Need help ASAP please all the number

Mathematics
1 answer:
Naddik [55]3 years ago
7 0

Answer:

doss

Step-by-step explanation:

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I don’t know how to do it, please teach me !!!
cricket20 [7]

As described in z-distribution the answers are given below:

a) The 95% confidence interval estimate for the population mean spending by a customer on visiting salon per month is given as follows: (747, 853).

b) The sampling error at 95% confidence level is of: $35.78.

What is a z-distribution ?

The normal distribution with a mean of 0 and a standard deviation of 1 is referred to as the standard normal distribution (also known as the Z distribution) (the green curves in the plots to the right). It is frequently referred to as the bell curve since the probability density graph resembles a bell.

solution:

The bounds of the confidence interval are given as follows:

In which:

is the sample mean.

z is the critical value.

n is the sample size. is the standard deviation for the population.

The parameters for this problem are given as follows:

Hence the lower bound of the interval is of:

800 - 200 x 1.96/square root of 55  = 747.

The upper bound of the interval is of:

800 + 200 x 1.96/square root of 55  = 853.

The sampling error for a sample size of 120 is calculated as follows:

200 x 1.96/square root of 120 = $35.78.

To learn more about the z-distribution from the given link

brainly.com/question/4079902

#SPJ1

5 0
1 year ago
A. 2<br> B. -2<br> C. 1/2<br> D. -1/2
allsm [11]

Rate of change is the slope.

The slope is the change in Y over the change in X:

Slope = (5- -3) / (2 - -2)

Slope = 8/4

Slope = 2

Answer: A.2

7 0
2 years ago
Element X decays radioactively with a half-life of eight minutes. If there are 800 g of element X, how long, to the nearest 10th
Harman [31]

Answer: 41.5 min

Step-by-step explanation:

This problem can be solved with the Radioactive Half Life Formula:  

A=A_{o}.2^{\frac{-t}{h}} (1)

Where:  

A=22 g is the final amount of the radioactive element

A_{o}=800 g is the initial amount of the radioactive element  

t is the time elapsed  

h=8 min is the half life of the radioactive element  

So, we need to substitute the given values and find t from (1):  

22 g=(800 g) 2^{\frac{-t}{8 min}} (2)  

\frac{22 g}{800 g}=2^{\frac{-t}{8 min}} (3)  

\frac{11}{400}=2^{\frac{-t}{8 min}} (4)  

Applying natural logarithm in both sides:  

ln(\frac{11}{400})=ln(2^{\frac{-t}{8 min}}) (5)  

-3.593=-\frac{t}{8 min}ln(2) (6)  

Clearing t:

t=41.46 min \approx 41.5 min This is the time elapsed

7 0
3 years ago
BRAINLIEST!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
dezoksy [38]
Can I im see the graph pleaseeewww
7 0
2 years ago
Read 2 more answers
The last number is 110
Vsevolod [243]

Answer:

70°

Step-by-step explanation:

90 + 20 + x = 180

110 + x = 180

x = 180 - 110

x = 70°

6 0
3 years ago
Read 2 more answers
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