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deff fn [24]
2 years ago
6

When does cell growth occur

Chemistry
2 answers:
hodyreva [135]2 years ago
7 0
Hi lovely,

Cell growth occurs during cell divison - this is also known as the "mother cell" dividing to create two "daughter cells".
Vlad [161]2 years ago
5 0
<span>in the top part of the lungs.</span>
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How many ethyne molecules are contained in 84.3 grams of ethyne (C2H2)?
ololo11 [35]
(~26grams/mole) and Avogadros # (6.022x10^23) 84.3grams x 1mole/26grams x 6.022x10^23 molecules/mole = 1.95x10^24 molecules of C2H2
6 0
2 years ago
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Consider an atom that has an electron in an excited state. The electron falls to a lower energy level. What effect does that hav
irinina [24]

On absorbing energy, an electron moves to an excited state (unstable state) from its ground state (stable state).  Since the electron is in unstable state so it tends to rearrange itself to return to its lowest energy state.  On returning to lowest energy state which is stable, it releases energy in the form of light.

Hence, option A that is the electron releases energy in the form of light on falling to lower energy state from excite state.

3 0
3 years ago
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Griffin made the following list of the different outer coverings of a plant. which part of his list is incorrect?
liraira [26]

Stamen is not an outer covering its the reproductive organ of the plants.

<h3>What is use of covering of Plants ?</h3>

Outer covering of plants is useful in protecting them from environment factors , it is useful in keeping the moisture intact inside the plants.

Among the different outer covering , Bark ,stamen , spines and fuzzy hairs

Bark , stamen and fuzzy hairs are all the outer covering of plants

Stamen is not an outer covering its the reproductive organ of the plants.

To know more about outer covering of Plants

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5 0
1 year ago
In going from room temperature 25° to 35 the rate of a reaction doubles calculate the activation energy for the reaction
Pepsi [2]

Answer:

52.9 KJmol-1

Explanation:

From;

log(k2/k1) = Ea/2.303 * R (1/T1 - 1/T2)

The temperatures must be converted to Kelvin;

T1 = 25° C + 273 = 298 K

T2= 35°C + 273 = 308 K

R= gas constant = 8.314 JK-1mol-1

Substituting values;

log 2 = Ea/2.303 * 8.314 (1/298 - 1/308)

Ea = 52.9 KJmol-1

4 0
3 years ago
Write the scientific notation in numerals. 1.2 x 104
ivanzaharov [21]
1.2*104 is 12000 it is easy just try ur best
8 0
3 years ago
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