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deff fn [24]
2 years ago
6

When does cell growth occur

Chemistry
2 answers:
hodyreva [135]2 years ago
7 0
Hi lovely,

Cell growth occurs during cell divison - this is also known as the "mother cell" dividing to create two "daughter cells".
Vlad [161]2 years ago
5 0
<span>in the top part of the lungs.</span>
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Coffee shops sell paper coffee<br> cups with cardboard sleeves<br> for customer safety. Why?
11111nata11111 [884]

The cardboard sleeves reduce the heatness from the coffee cup. So then the cosumer does not get a burn.

4 0
2 years ago
PLS HELP!! <br> Balance this equation: __H2+ 2 O2---&gt; 2 H2O
alekssr [168]

Answer:

 2H₂   +   O₂  →   2H₂O

Explanation:

The expression of the equation is given as:

              _H₂   +   2O₂  →   2H₂O

Now for expression above,

                           Reactants                                          Products

H                              2                                                            4

O                              4                                                           2

to balance the equation, we use 2 moles of hydrogen gas and 1 mole of oxygen gas;

           2H₂   +   O₂  →   2H₂O

6 0
3 years ago
Two atoms of the same element
kotykmax [81]

Answer:

Isotope

Explanation:

5 0
2 years ago
How mariy molecules of water are in a 500.3 g sample?
JulijaS [17]

Answer:

1.67×10^25 molecules

Explanation:

No of molecules = no of moles × Avogadros number

No of moles= mass in gram / molar mass

No of moles of water in given sample = 500.3/18

= 27.79 moles

No of molecules = 27.79× 6.02×10^ 23

= 167.32×10^23 or 1.67×10^25

3 0
3 years ago
During your reaction, you added 0.3 mL concentrated H2SO4 (18.4 M) as the catalyst. At the end of the reaction, you need to add
sattari [20]

Answer:

58.72 mL

Explanation:

The chemical equation for the neutralization reaction is :

H₂SO₄(aq) + Na₂CO₃(s)  --------------> Na₂SO₄(aq) + H₂O(l) + CO₂(g)

where;

M₁ = Molarity of H₂SO₄

M₂= Molarity of Na₂CO₃

V₁= Volume of H₂SO₄

V₂ = Volume of Na₂CO₃

Given that :

M₁ = 18.4 M

V₁= 0.3 mL

10% Na₂CO₃ means 100 g of solution contain 10 g of Na₂CO₃

i.e. 10 g Na₂CO₃ dissolved and diluted to 100 mL water.

Molar mass of Na₂CO₃ = 106 g/mol

106 g Na₂CO₃ dissolved in 100 mL will give 0.1 M Na₂CO₃ solution.

However;

If, 106 g Na₂CO₃ ≡ 0.1 M Na₂CO₃

Then, 10 g Na₂CO₃ ≡  'A' M  of Na₂CO₃

By cross multiplying; we have:

106 × A = 10 × 0.1

106 × A = 1

A = (1/106) M/100 mL

A = 10 x (1/106)) M/L

A = (10/106) M

A = 0.094  M

Therefore,the molarity of 10% Na₂CO₃ solution is 0.094 M.

For the Neutralization equation, we have:

M₁V₁ = M₂V₂

18.4×0.3 = 0.094×V₂

Making V₂  the subject of the formula;we have:

V_2 = \frac{18.4*0.3}{0.094}

V₂ = 58.72 mL

4 0
3 years ago
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