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2 years ago

When does cell growth occur

2 answers:

7 0

Hi lovely,

Cell growth occurs during cell divison - this is also known as the "mother cell" dividing to create two "daughter cells".

Vlad [161]2 years ago

5 0

in the top part of the lungs.

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The metalloid that has three valence electrons is .

lawyer [7]

Answer:

Boron

Explanation:

4 0

2 years ago

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1. What would happen to the position of equilibrium when the following changes are made to the reaction below? 2Hg3O (g) ↔ 6Hg (

Mademuasel [1]

What is your answer I can help you)

4 0

2 years ago

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(40) If a hypothesis is proven correct, a theory is formulated. True or false

Snezhnost [94]

Answer: False, I believe.

Explanation: If a Hypothesis is proven correct, then another experiment to strengthen that Hypothesis is should be done.

8 0

2 years ago

To a 25.00 mL volumetric flask, a lab technician adds a 0.150 g sample of a weak monoprotic acid, HA , and dilutes to the mark w

Elis [28]

Answer: The number of moles of weak acid is $4.24\times 10^{-3}$ moles.

Explanation:

To calculate the moles of KOH, we use the equation:

$\text{Molarity of the solution}=\frac{\text{Moles of solute}}\text{Volume of solution (in L)}}$

We are given:

Volume of solution = 43.81 mL = 0.04381 L (Conversion factor: 1L = 1000 mL)

Molarity of the solution = 0.0969 moles/ L

Putting values in above equation, we get:

$0.0969mol/L=\frac{\text{Moles of KOH}}{0.04381}\\\\\text{Moles of KOH}=4.24\times 10^{-3}mol$

The chemical reaction of weak monoprotic acid and KOH follows the equation:

$HA+KOH\rightarrow KA+H_2O$

By Stoichiometry of the reaction:

1 mole of KOH reacts with 1 mole of weak monoprotic acid.

So, $4.24\times 10^{-3}mol$ of KOH will react with = $\frac{1}{1}\times 4.24\times 10^{-3}=4.24\times 10^{-3}mol$ of weak monoprotic acid.

Hence, the number of moles of weak acid is $4.24\times 10^{-3}$ moles.

6 0

3 years ago

Calculate the concentration of formate in a 100mm solution of formic acid at ph 4.15. The pka for formic acid is 3.75

MissTica

The molarity of formic acid is 100 mM or $100\times 10^{-3}M$ . The dissociation reaction of formic acid is as follows:

$HCOOH\leftrightharpoons HCOO^{-}+H^{+}$

The expression for dissociation constant of the reaction will be:

$K_{a}=\frac{[HCOO^{-}][H^{+}]}{[HCOOH]}$

Rearranging,

$[HCOO^{-}]=\frac{K_{a}[HCOOH]}{[H^{+}]}$

Here, pH of solution is 4.15 thus, concentration of hydrogen ion will be:

$[H^{+}]=10^{-pH}=10^{-4.15}=7.08\times 10^{-5}M$

Similarly, $pK_{a}=3.75$ thus,

$[K_{a}=10^{-pK_{a}}=10^{-3.75}=1.78\times 10^{-4}M$

Putting the values,

$[HCOO^{-}]=\frac{(1.78\times 10^{-4}M)(100\times 10^{-3}M)}{(7.08\times 10^{-5}M}=0.2511 M$

Therefore, the concentration of formate will be 0.2511 M.

4 0

2 years ago