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Shtirlitz [24]
3 years ago
9

Hypothermic body temperature can range from 28.7 °C to 35.5 °C. What is this range in degrees Fahrenheit?

Chemistry
1 answer:
Amanda [17]3 years ago
5 0
Solution:

To convert Celsius to Fahrenheit, the formula to be used is (C * 9/5) + 32

So in our given, 28.7 degrees Celsius:

Farenheit = (28.7 * 9/5) + 32
= 51.66 + 32
= 83.66 degrees Fahrenheit

Next, 35.5 degrees Celsius:
Farenheit = (35.5 * 9/5) + 32
= 63.9 + 32
= 95.9 degrees Fahrenheit

So in Fahrenheit, the range would be 83.66 – 95.9 degrees Fahrenheit.
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What is the mass of a bar of aluminum with length 5.3cm, width 0.32 cm and height 2.34cm? The density of aluminum is 2.70g/cm3.
Tatiana [17]

Answer:

<h2>mass = 10.72 g</h2>

Explanation:

Density of a substance can be found by using the formula

Density =  \frac{mass}{volume}

Making mass the subject we have

mass = Density \times volume

From the question

Density = 2.70 g/cm³

We assume that the aluminum is a cuboid

and volume of a cuboid is given by

Volume = length × width × height

length = 5.3 cm

width = 0.32 cm

height = 2.34 cm

Volume = 5.3 × 0.32 × 2.34 = 3.97 cm³

Substitute the values into the above and solve for the mass

We have

mass = 2.70 × 3.97

We have the final answer as

<h3>mass = 10.72 g</h3>

Hope this helps you

6 0
3 years ago
PLEASE HELP!!!
neonofarm [45]

Answer:

Cl_2+2NaI\rightarrow I_2+2NaCl

Explanation:

Hello there!

In this case, according to the described chemical reaction, Cl2 replaces iodine in NaI in order to produce I2 and NaCl:

Cl_2+NaI\rightarrow I_2+NaCl

It is possible to realize how chlorine replaces iodine in agreement with the single displacement reaction. Moreover, since chlorine and iodine atoms are not correctly balanced, we add a 2 in front of both NaI and NaCl in order to do so:

Cl_2+2NaI\rightarrow I_2+2NaCl

Best regards!

8 0
2 years ago
Why are models used to represent Atoms
Keith_Richards [23]

Answer:

C

Explanation:

5 0
2 years ago
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What numbers are considered significant?
AleksAgata [21]

Answer:

6/5/8/9

Explanation:

5 0
2 years ago
A 4.00L flask containing Ne at 25 C and 6.00 atm is joined by a valve to an 8.00 L flask Ar at 25 C and 2.00 atm.
timama [110]

Answer:

P=3.33atm

Explanation:

Hello!

In this case, since know the volume, temperature and pressure of the initial containers, we can compute the moles of each gas prior to the opening of the valve as shown below:

n_{Ne}=\frac{6atm*4L}{0.08206\frac{atm*L}{mol*K}*298.15K} =0.981molNe\\\\n_{Ar}=\frac{2atm*8L}{0.08206\frac{atm*L}{mol*K}*298.15K} =0.654molAr

Next, we add them up to obtain the total moles:

n_T=0.981mol+0.654mol=1.635mol

Now, the total volume:

V_T=4.00L+8.00L=12.00L

Finally, the total pressure is computed by using the ideal gas equation:

P=\frac{1.635mol*0.08206\frac{atm*L}{mol*K}*298.15K}{12.00L}\\\\P=3.33atm

Best regards!

6 0
3 years ago
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