D - density: 40 mg/ml
V - volume: 175 ml
m - mass: ??
__________
d = m/V
m = V×d
m = 175×40
m = 7000 mg = 7 g
:•)
<span>When completing an experiment, results will be much more accurate if multiple trials are completed and the results averaged. True. That's because you may get different results each time. </span>
When uranium<span> comes in contact with oxygen in the air, it rusts, just like iron does, but </span>uranium<span> rust is black and not red. Like other heavy </span>atoms <span>such as iron, </span>uranium atoms<span> have more neutrons than they do protons. Not all </span>uranium atoms<span> have the </span>same<span> number of neutrons.</span>
Answer: Volume occupied by given neon sample at standard condition is 123.84 L.
Explanation:
Given: 
= 105 L, 
, 
= 985 torr
At standard conditions,
= 273 K, 
= 760 K, 
= ?
Formula used to calculate the volume is as follows.
Substitute the values into above formula as follows.
Thus, we can conclude that volume occupied by given neon sample at standard condition is 123.84 L.
