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Veronika [31]
3 years ago
12

In a salt water solution, what is the water?

Chemistry
2 answers:
antoniya [11.8K]3 years ago
7 0
A solute, hope it helps
Aleksandr-060686 [28]3 years ago
5 0

Answer:

In a salt water solution, water is the solvent.

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Imagine two solutions with the same concentration and the same boiling point, but one has benzene as the solvent and the other h
aleksandrvk [35]

Answer:

Concentration = 1.32 m

Boiling point = 83.44^{0}C

Explanation:

Let the boiling point of two solutions = T

Let the molal concentration of the two solutions= m

The relation between elevation in boiling point and molal concentration is:

elevationinboiling point=K_{b}Xmolality

i) For benzene

T-80.1=2.53Xm

T=2.53m+80.1 ....(1)

ii) For carbon tetrachloride

T-76.8=5.03Xm

T=5.03Xm+76.8 ...(2)

Equating the two equations:

5.03Xm+76.8=2.53m+80.1\\m=1.32molal

Putting value of "m" in equation "1"

T=2.53(1.32)+80.1=83.44^{0}C

5 0
3 years ago
When taphonomy records show a short PMI and warm, humid conditions, the degree of certainty is probably _____.
puteri [66]

The degree of certainty is high.

7 0
4 years ago
Read 2 more answers
How much heat is necessary to raise the temperature of a 15.0 g metal from 15.0 C to 25.0 C if the specific heat of that metal i
Bumek [7]

The solution would be like this for this specific problem:

<span><span>
E</span>=</span><span>mc</span>ΔT<span> <span>
= (</span>15<span> g</span><span>)(</span>1.91<span> <span>J<span><span>g∘</span>C</span></span>)(</span>25<span><span> ∘</span>C</span>−15<span><span> ∘</span>C</span><span>)
</span></span>= 28.65 * 10
= 286.5

<span>

I hope this helps and if you have any further questions, please don’t hesitate to ask again. </span>

5 0
3 years ago
There are three stable isotopes of magnesium. Their masses are 23.9850, 24.9858, and 25.9826 u. If the average atomic mass of ma
olganol [36]

Answer:

²⁵ Mg = 10.00%

²⁶ Mg = 11.0%

Explanation:

Given that:

Magnesium ²⁴Mg has an abundance of 78.99%

Hence, (100 - 78.99)% = 21.01%

21.01% is the abundance of ²⁵ Mg and ²⁶ Mg

Suppose,

²⁵ Mg = x

²⁶ Mg = (21.01 - x)%

Then;

avg. atomic mass = \dfrac{78.99}{100 }(23.9850)+\dfrac{x}{100}(24.9858) +\dfrac{21.01-x}{100}(25.9826)

where the avg. atomic mass = 24.3050

∴

24.3050 \times 100 = {78.99}(23.9850)+\dfrac{x}{100}(24.9858) +\dfrac{21.01-x}{100}(25.9826)

2430.5 = 2440.46915 -0.9968 x

0.9968x = 2440.46915 - 2430.5

0.9968x = 9.96915

x  =  9.96915/0.9968

x  =  10.00%

∴ Recall that:

²⁵ Mg = x

²⁶ Mg = (21.01 - x)%

²⁵ Mg = 10.00%

²⁶ Mg = (21.01 - 10.00)%

²⁶ Mg = 11.0%

3 0
4 years ago
If 10.5-g of Na2SO4 are actually recovered experimentally, that is the percent yield?
SVEN [57.7K]
<span>"If they recover 10.5 it means you shall add with the limiting 10.8, giving you 21.3g out of 142 times 100, giving 15%, I believe."
By anonymous on openstudy.com

</span>
5 0
3 years ago
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