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sladkih [1.3K]
3 years ago
14

Two students push a heavy crate across the floor. John pushes with a force of 185 N due east and Joan pushes with a force of 165

N at 30∘north of east. What is the resultant horizontal force on the crate?

Physics
1 answer:
zubka84 [21]3 years ago
3 0

Answer:

327.894 N

Explanation:

We have given two forces Jhon pushes with a force of 185 N in east direction and Joan pushes with a force of 165 N at 30° north of east which is clearly shown in figure

We fave to find the total horizontal force

So total horizontal force will be F_X=185+165cos30^{\circ} =327.894 N ( total horizontal force will be sum of force in the east direction and horizontal component of the force in north- east direction)

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The graph shows at which point acceleration of an object is higher and lower so we can conclude that point A has the largest magnitude of acceleration as compared to other points on the position verses time graph.

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What is the difference between the law of conservation of energy and conserving energy
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<span>law of conservation of </span>energy<span> is </span><span><span>states that energy of the universe remains constant cant be created nor destroyed and conserving energy is not using as much power as you was like trying to make power bill lower while law of conservation is constant </span> </span>


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2 years ago
An electric field from a charge has a magnitude of 1.5 × 104 N/C at a certain location that points inward. If another charge wit
zysi [14]

Answer:

-0.045 N, they will attract each other

Explanation:

The strength of the electrostatic force exerted on a charge is given by

F=qE

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In this problem,

q=3.0\cdot 10^{-6}C

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So the strength of the electrostatic force is

F=(-3.0\cdot 10^{-6}C)(1.5\cdot 10^4 N/C)=-0.045 N

Moreover, the charge will be attracted towards the source of the electric field. In fact, the text says that the electric field points inward: this means that the source charge is negative, so the other charge (which is positive) is attracted towards it.

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3 years ago
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What is the maximum rated voltage for a 100 ohm 1/4 watt resistor?
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This can be solve using the formula P = I^2 * Rwhere P is the powerI is the CurrentR is the resistanceP = I^2 * R
1/4 Watt = I^2 * 100 ohm solve for II^2 = 1/400  I = 0.05 amps then using the formula to solve for the voltage:V = I * RV = 0.05 amps * 100 ohms V = 5 volts
3 0
2 years ago
Compare and contrast electric potential energy and electric potential difference? Explain.
forsale [732]

Answer:

<u><em>Electric Potential Energy:</em></u>

The energy that is needed to move a charge against an electric firld is called Electric Potential Energy

<u><em>Electric Potential Difference:</em></u>

The amount of work done in carrying a unit charge from one point to an other in an electric field is called Electric Potential Difference.

<u><em>Relation:</em></u>

Relation between Electric potential and electrical potential energy is given by

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it means electric potential difference is the difference in electric potential energy divided by the charge.

6 0
2 years ago
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