Im going with B for transverse wave
in a monoprotic acid , its capable of dissociating 1 H⁺ ion . The base used is NaOH which is capable of giving out 1 OH⁻ ion.
Therefore both base and acid react in a 1:1 molar ratio, that means for each 1 mol of monoprotic acid there is , it requires 1 mol of NaOH to be neutralised.
So at equivalence point the number of acid moles present should react with an equal number of NaOH moles to be neutralised
number of NaOH moles added - concentration x volume
number of NaOH moles - 0.0950 mol/dm³ x 27.4 x 10⁻³ dm³ = 0.00260 mol
since molar ratio of NaOH to Acid is 1:1
number of acid moles present is also - 0.00260 mol
mass of acid added - 0.2140 g
we can find molar mass using following equation
molar mass = mass / number of moles
molar mass = 0.2140 g / 0.00260 mol = 82.3 g/mol
therefore molar mass of monoprotic acid is 82.3 g/mol
Explanation:
An elastic band is hung on a hook and a mass is hung on the lower end of the band. When the mass is pulled downward and then released, it vibrates vertically. The equation of motion is given by :

Where
s is in centimeters
t is in seconds
Velocity of the particle, 

Acceleration of the particle, 

Hence, this is the required solution.
Speed = distance / time = 55 / 0.75 = 73.3 miles per hour.
The force of friction is 300 N
Explanation:
We can solve the problem by applying Newton's second law of motion: in fact, the net force acting on an object is equal to the product between the mass of the object and its acceleration. So we can write

where
is the net force acting on the object
m is its mass
a is its acceleration
For the cart in this problem, we have two forces acting on it:
- The force of push, F = 500 N, forward
- The force of friction,
, backward
So Newton's second law can be rewritten as

where
m = 50 kg
is the acceleration of the cart
And solving for
, we find the force of friction:

Learn more about force of friction:
brainly.com/question/6217246
brainly.com/question/5884009
brainly.com/question/3017271
brainly.com/question/2235246
#LearnwithBrainly