<span>Work: W = Fd. 50(distance) multiplied by 90(force) would equal 4500 J or, answer D</span>
Answer:
0.466 (3 sig. fig.)
Explanation:
Frictional force acting on the box = 5.00×10^2xsin25
Normal force acting on the box = 5.00×10^2xcos25
coefficient of friction = 0.466 (3 sig. fig.)
Velocity is displacement/time
(Displacement is the overall change in distance)
So you’ll want to divide 200 by 25, which should give you:
8 m/s
Given :
Liquid is poured into a burrete so that it reads 14cm³.
50 drops were run each of volume 0.1cm³ .
To Find :
The volume of liquid in burrete after 50 drops.
Solution :
Volume of each drop, v = 0.1 cm³.
Initial volume in burrete, V = 14 cm³.
Now, volume left after droping 50 drops are :

Therefore, the volume left in burrete is 9 cm³ .