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qwelly [4]
3 years ago
13

Benzene has a specific gravity of 0.88. if it was spilled in a river what would it do?

Chemistry
1 answer:
Gelneren [198K]3 years ago
4 0
As we know,
                    Density of Benzene  =  876 Kg/m³
And,
                    Density of Water       =  997 Kg/m³
So,
     Specific Gravity is calculated as,

                     Specific Gravity  =  Density of Benzene / Density of Water

                     Specific Gravity    =   876 Kg/m³ / 997 Kg/m³

                     Specific Gravity    =  0.878

Every object having specific gravity less than 1 will float on water and if value is greater than 1 then it will sink.

Benzene being non-polar in nature does not mix with water and due to less density it will float on the surface of water.
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QUESTION THREE
BartSMP [9]

Answer:

Odds to be given for an event that either Romance or Downhill wins is 11:4

Explanation:

Given an odd, r = a : b. The probability of the odd, r can be determined by;

     Pr(r) = \frac{a}{b} ÷ (

So that;

Odd that Romance will win = 2:3

Pr(R) = \frac{2}{3} ÷ (

        = \frac{2}{3} ÷ \frac{5}{3}

       = \frac{2}{5}

Odd that Downhill will win = 1:2

Pr(D) = \frac{1}{2} ÷ (

        =  \frac{1}{2} ÷ \frac{3}{2}

        = \frac{1}{3}

The probability that either Romance or Downhill will win is;

Pr(R) + Pr(D) = \frac{2}{5} +  \frac{1}{3}

                    = \frac{11}{15}

The probability that neither Romance nor Downhill will win is;

Pr(neither R nor D) = (1 - \frac{11}{15})

                               = \frac{4}{15}

The odds to be given for an event that either Romance or Downhill wins can be determined by;

                               = Pr(Pr(R) + Pr(D)) ÷ Pr(neither R nor D)

                               = \frac{11}{15} ÷ \frac{4}{15}

                              = \frac{11}{4}

Therefore, odds to be given for an event that either Romance or Downhill wins is 11:4

8 0
2 years ago
A sample of 0.370 mol of a metal oxide (m2o3) weighs 55.45 g. how many grams of o are in the sample?
Wewaii [24]
0.370 mol metal oxide = 55.45 g 

<span>1 mol = 55.45/0.370 = 149.86 g </span>

<span>in 1 mol there are 3 mol O = 16 * 3 = 48 g of O </span>

<span>there is 48/149.86 * 100% O in the sample </span>

<span>the sample has 48/149.86 * 0.370 = 0.119 g O</span>
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Binary compounds are formed by ............... ............... elements.
goblinko [34]

Answer: i think its A diatomic compound..

Explanation: hope i helped! sorry if im wrong!

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<span>a) movement of heat through space </span>
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The answer is 6 moles of water will be produced.
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