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qwelly [4]
3 years ago
13

Benzene has a specific gravity of 0.88. if it was spilled in a river what would it do?

Chemistry
1 answer:
Gelneren [198K]3 years ago
4 0
As we know,
                    Density of Benzene  =  876 Kg/m³
And,
                    Density of Water       =  997 Kg/m³
So,
     Specific Gravity is calculated as,

                     Specific Gravity  =  Density of Benzene / Density of Water

                     Specific Gravity    =   876 Kg/m³ / 997 Kg/m³

                     Specific Gravity    =  0.878

Every object having specific gravity less than 1 will float on water and if value is greater than 1 then it will sink.

Benzene being non-polar in nature does not mix with water and due to less density it will float on the surface of water.
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Answer:

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Explanation:

Given data:

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Solution;

The given problem will solve by using Avogadro number.

It is the number of atoms , ions and molecules in one gram atom of element, one gram molecules of compound and one gram ions of a substance.

The number 6.022 × 10²³ is called Avogadro number.

For example,

1 mole = 6.022 × 10²³ molecules of water

7.1×10²⁵ molecules of water × 1 mol / 6.022 × 10²³ molecules of water

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