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2 years ago

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Identify and label the bronsted lowry acid, its conjugate base, the bronsted-lowry base, and its conjugate acid in each of the f

ollowing equations (a, b, ca, cb):
a. hbr h2o --> h30 br-
b. NO-2 H2o --> HNO2 OH-

1 answer:

ICE Princess25 [194]2 years ago

7 0

Explanation:

A bronsted lowry acid is any species that can donate a hydrogen proton (H+) to another molecule.

A bronsted lowry base is any species that can receive a hydrogen proton (H+) from another molecule.

a. hbr h2o --> h30+ br-

The Bronsted-Lowry acid is HBr

It's conjugate base is Br-

The Bronsted-Lowry base is H2O

It's conjugate acid is h30+

b. NO-2 H2o --> HNO2 OH-

The Bronsted-Lowry acid is H2O

It's conjugate base is OH-

The Bronsted-Lowry base is NO-2

It's conjugate acid is HNO2

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1 year ago

4) The initial rate of the reaction between substances P and Q was measured in a series of

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Answer:

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$rate= k[P]^{2} [Q]\\=>[Q]=\frac{rate}{k.[P]^{2} } \\and \\\\\\\ [P]=\sqrt{\frac{rate}{k.[Q]} }$

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From the first row,

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Second row:

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2 years ago

Upper n subscript 2 (g) plus 3 upper H subscript 2 (g) double-headed arrow 2 upper N upper H subscript 3 (g). At equilibrium, th

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3 years ago

Titanium has an HCP crystal structure, a c/a ratio of 1.669, an atomic weight of 47.87 g/mol, and a density of 4.51 g/cm3. Compu

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Answer : The atomic radius for Ti is, $1.45\times 10^{-8}cm$

Explanation :

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First we have to calculate the volume of HCP crystal structure.

Formula used :

$\rho=\frac{Z\times M}{N_{A}\times V}$ .............(1)

where,

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Now put all the values in above formula (1), we get

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Formula used :

$V=6R^2c\sqrt{3}$

Given:

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Now put (c = 1.669 a) and (a = 2R) in this formula, we get:

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$V=(1.669)\times (12\sqrt{3})R^3$

Now put all the given values in this formula, we get:

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$R=1.45\times 10^{-8}cm$

Therefore, the atomic radius for Ti is, $1.45\times 10^{-8}cm$

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2 years ago