If the dehydration reaction of an alcohol is successful. The changes would be seen in the IR spectrum for the product compared to the starting material are as,
- The O-H and C-O band is disappear from stating material
- The addition of a C-C double bond band in the product.
In dehydration reaction of alcohol ( O-H and C-O bond ) contain , the water molecule (
) is release from the reactant and C-C double bond is form which is known as alkene in the product .
The reactant and product have different structure. To determine the structure of the compound IR spectroscopy is used. In IR spectrum the peak corresponds to 3400-3600 cm is missing in the product of dehydration reaction of an alcohol. It means O-H band is disappear from stating material.
learn about IR SPECTRUM
brainly.com/question/15452269
#SPJ4
Its me and me= me.serdtghmjhgfdsaazSDFGHYYUJYHGFDSXAZSDFGHYUJIKUJYHGTFDSXAZSXDCFGHJIKUJHGGFVCDXZVFGHYU7GBFVC CVFGTY67YTGFVC VFGTY56YTGBV VBG
Try out answer C magnesium oxides melting point is almost 5 times higher than magnesium
<span>Answer:
molality = (moles of solute) / (kilogram of solvent)
moles of solute = (75.2 g AgClO4) / (mole mass AgClO4)
moles of solute = (75.2 g AgClO4) / (207.3206 g/mol)
moles of solute = 0.3627232 mol
molality = (0.3627232 mol) / (0.0752 Kg)
molality = 4.8234468 m or 4.82 m rounded to three significant figures </span>