Answer:
The allowable values for the principle quantum number (n) are integers greater than zero.
The allowable values for the angular momentum quantum number (l) are integers from 0 to n-1.
The allowable values for the magnetic quantum number (ml) are integers from -l to l.
The allowable values for the spin quantum number (ms) are -1/2 and 1/2.
Explanation:
<em>Identify allowable combinations of quantum numbers for an electron. Select all that apply.</em>
- <em>The allowable values for the principle quantum number (n) are integers greater than zero. </em>TRUE. The principal quantum number (n) represents the level of energy in which an electron is and can take positive integer values.
- <em>The allowable values for the angular momentum quantum number (l) are integers from 0 to n-1.</em> TRUE. The angular quantum number (l) represents the sublevel of energy and the kind of orbital an electron is in and can take integer values from 0 to n-1. For instance, if n = 1, l can take the value "0", which represents the sublevel and orbital "s".
- <em>The allowable values for the magnetic quantum number (ml) are integers from -l to l.</em> TRUE. The magnetic quantum number (ml) represents the orientation of an orbital in space and can take integers values from -l to +l. For instance, if l = 1 (p orbital), ml can take the values -1, 0 and 1, which refer to orbitals px, py and pz.
- <em>The allowable values for the spin quantum number (ms) are -1/2 and 1/2. </em>TRUE. The spin quantum number (ms) represents the spin of the electron and can take values -1/2 and +1/2.
Gamma rays have the highest penetrating power so it can only be stopped by thick layers of dense metal. :)
Answer:
my mass turned into gasses and other substances besides ash
Explanation:
burning a log products smoke and ash. the smoke takes some mass and the ash takes the rest.
Answer:
300 mL
Explanation:
the unit formula of calcium phosphate is Ca3(PO4)2
molar mass of Ca3(PO4)2 = (3×40 + 2×31 + 8×16) g/mol = 310 g/mol
n = m/M = 35 g/(310 g/mol)
c = n/V
V = n/c = [35 g/(310 g/mol)]/0.375 mol/L
V = 0.30 L = 300 mL
Answer:
Hope this helps
Explanation:
https://seagrant.whoi.edu/wp-content/uploads/2018/05/ESTIMATING-POPULATION-SIZE-1.pdf