<u>The two ways to find acceleration in non uniform motion are as follows:</u>
<u>Explanation:</u>
Non-uniform acceleration comprises the most common description of motion. Acceleration refers to the rate of changes of velocity per unit time. Basically, it implies that acceleration changes during motion. This variety can be communicated either as far as position (x) or time (t).
Accordingly, non-uniform acceleration motion can be carried out in 2 ways:
Calculus analysis is general and accurate, but limited to the availability of speed and acceleration expressions. It is not always possible to get the expression of motion attributes in the form "x" or "t". On the other hand, the graphic method is not accurate enough, but it can be used accurately if the graphic has the correct shapes.
The use of calculations involves differentiation and integration. Integration enables evaluation of the expression of acceleration of speed and expression of movement at a distance. Similarly, differentiation allows us to evaluate expression of speed position and expression speed to acceleration.
Answer:
Explanation:
Hello! To solve this problem we must be clear about the concept of energy conservation, and kinetic energy with the following sentence
The kinetic energy of the two cars (v = 1.2m / S) plus the kinetic energy of the third car (v = 3.5m / S) must be equal to the kinetic energy of the three cars together.
The kinetic energy is calculated by the following equation.

m= mass of the cars=26500kg
V=speed
E=kinetic energy
taking into account the above, the following equation is inferred
1= the cars are separated
2=
the cars are togheter
E1=E2

where
m= mass of each car
V1= 1.2m/s
Va=3.5,m/S

m= mass of each car
V=speed (in m/s) of the three coupled cars after the first couples with the other two
Solving



the speed of the three coupled cars after the first couples with the other two is 2.245m/s
A)
At time = .003 hr
B)
90* (3*10^-3) = .27km
C)
.005 hr
D)
Car A = 150 * (.005) = .75km
Car B = (90 * (.005) = .45 km
E)
Car A = 150 * (0.008) = 1.2 km
Car B = 90 * (0.008) = 0.72 km
Car A is ahead
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